尝试财产以后这样的:
with tmp as (
select f0.*, rownumber() over(partition by f0.ORDER, f0.POSTCODE) rang
from your table f0
)
select
f1.ORDER, f1.POSTCODE, f1.Quantity AmbientQuantity, f1.Value Ambientvalue,
f2.Quantity FVQuantity2, f2.Value FvVAlue2,
f3.Quantity FVQuantity3, f2.Value FvVAlue3,
f4.Quantity FVQuantity4, f2.Value FvVAlue4
from tmp f1
left outer join tmp f2 on (f1.ORDER, f1.POSTCODE)=(f2.ORDER, f2.POSTCODE) and f2.rang=2
left outer join tmp f3 on (f1.ORDER, f1.POSTCODE)=(f3.ORDER, f3.POSTCODE) and f3.rang=3
left outer join tmp f4 on (f1.ORDER, f1.POSTCODE)=(f4.ORDER, f4.POSTCODE) and f4.rang=4
where f1.rang=1
感谢迈克尔。上述SQL按预期工作。 –
太棒了 - 请将其标记为答案 - 谢谢 – MichaelTiefenbacher