我想计算索引[0] [2]中的总值,以前的值为0,但我已经用计算结果“1/y”替换并显示它,并且当我计算合计值,即求和值是以前的值,该值包含“0”,这是我的代码,使用新值计算JTable列中的总值
//observation table
//0 1 2 3 4 5 6
titleColumn = new Object[]{"Time (Second)","Medicine", "1/y","x2", "X/Y", "Y^", "Error"};
//0 1 2 3 4 5 6
allData = new Double[][] {{1.0,1.02,0.0,0.0,0.0,0.0,0.0},
{2.0,0.667,0.0,0.0,0.0,0.0,0.0},
{3.0,0.367,0.0,0.0,0.0,0.0,0.0},
{4.0,0.278,0.0,0.0,0.0,0.0,0.0},
{5.0,0.237,0.0,0.0,0.0,0.0,0.0},
{6.0,0.187,0.0,0.0,0.0,0.0,0.0},
{7.0,0.155,0.0,0.0,0.0,0.0,0.0},
{8.0,0.156,0.0,0.0,0.0,0.0,0.0},
{9.0,0.142,0.0,0.0,0.0,0.0,0.0},
{10.0,0.111,0.0,0.0,0.0,0.0,0.0},
{11.0,0.12,0.0,0.0,0.0,0.0,0.0},
{12.0,0.097,0.0,0.0,0.0,0.0,0.0},
{13.0,0.099,0.0,0.0,0.0,0.0,0.0},
{14.0,0.089,0.0,0.0,0.0,0.0,0.0},
{15.0,0.079,0.0,0.0,0.0,0.0,0.0},
{0.0,0.0,0.0,0.0,0.0,0.0,0.0}};
tableModelObservation = new DefaultTableModel(allData, titleColumn);
tableObservation.setModel(tableModelObservation);
int row,column,inputRow,inputColumn;
//index [0][2] was replaced with calculation 1/y
row = 0;
column = 1;
inputRow = 0;
inputColumn = 2;
double onePerY = 0;
for(int a=0;a<allData.length;a++){
onePerY = 1/allData[row][column];
//is this the way to use getValueAt() and for indicating that the dependent cell has been change ?
tableObservation.getModel().getValueAt(row, column);
tableObservation.firePropertyChange("1/y", inputRow, inputColumn);
tableObservation.getModel().setValueAt(onePerY, inputRow, inputColumn);
inputRow++;
row++;
}
//calculation total 1/y, summing is still using previous value "0"
row = 0;
column = 2;
inputRow = 15;
inputColumn = 2;
double totalOnePerY = 0;
for (int a=0;a<allData.length;a++){
totalOnePerY += allData[row][column];
row++;
}
//displaying result in row index[15] and column index[2]
tableObservation.getModel().setValueAt(totalOnePerY, inputRow, inputColumn);
此列中的值“1/y”的计算处理之后
应该怎么办,能够使用新值来加总它? 所有你给的,我希望它的帮助,谢谢
另请参阅这些[相关示例](http://stackoverflow.com/a/13628183/230513)。 – trashgod
谢谢你trashgod,我已经添加了我的代码与getValueAt(),但结果是相同的 – irwansyahazniel
@irwansyahazniel:我详细阐述了上面;一个类似的问题进行了审查[这里](http://stackoverflow.com/q/11223586/230513)。 – trashgod