我刚刚开始使用Spring Security 3.1,但还没有找到一种方法将它放在JSF 2.1 Web应用程序之上。我目前有:JSF 2.1 web应用程序的Spring Security
一个web.xml有:
<context-param>
<param-name>contextConfigLocation</param-name>
<param-value>classpath:applicationContext-business.xml
/WEB-INF/applicationContext-security.xml
</param-value>
<filter>
<filter-name>springSecurityFilterChain</filter-name>
<filter-class>org.springframework.web.filter.DelegatingFilterProxy</filter-class>
</filter>
<filter-mapping>
<filter-name>springSecurityFilterChain</filter-name>
<url-pattern>/*</url-pattern>
</filter-mapping>
<listener>
<listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
</listener>
而我的applicationContext-security.xml文件:
<beans:beans xmlns="http://www.springframework.org/schema/security"
xmlns:beans="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://www.springframework.org/schema/beans
http://www.springframework.org/schema/beans/spring-beans-3.0.xsd
http://www.springframework.org/schema/security
http://www.springframework.org/schema/security/spring-security-3.1.xsd">
<http pattern="/resources/**" security="none" />
<http use-expressions="true">
<intercept-url pattern="/administracion/departamentos/**" access="recursoshumanos" />
<intercept-url pattern="/administracion/derechos/**" access="recursoshumanos" />
<intercept-url pattern="/administracion/diasfestivos/**" access="recursoshumanos" />
<intercept-url pattern="/administracion/dias/**" access="recursoshumanos" />
<intercept-url pattern="/administracion/solicitudes/**" access="recursoshumanos" />
<intercept-url pattern="/administracion/empleados/**" access="recursoshumanos" />
</http>
<authentication-manager>
<authentication-provider>
<user-service>
<user name="rod" password="koala" authorities="recursoshumanos" />
<user name="dianne" password="emu" authorities="jefe" />
<user name="scott" password="wombat" authorities="jefe" />
</user-service>
</authentication-provider>
</authentication-manager>
我猜这个例子会窝与常规的.jsp rk,但我可能会错过其他步骤,使其与JSF,不幸的是,我一直没能找到一个完整的工作示例到目前为止。我需要做什么?谢谢!
编辑:问题是,我仍然可以自由地导航到应用程序的安全区域,而无需登录
编辑:BTW,我只注意到一个过滤器,Web应用程序的根呢确实触发了认证机制。尽管如此,它仍然失败了。
激活spring安全包的调试级别。它会为您提供更多信息。 – jddsantaella 2012-03-14 22:18:20