django-filter use paginations

Question

我使用django-filter包在我的列表视图中提供搜索功能。

现在我想为该视图添加分页。
我试图将分页结合到一个过滤的查询集，但我不知道如何继续下去。

到目前为止，我已经尝试了views.py如下：

def search(request): 
    qs = local_url.objects.filter(global_url__id=1).all() 
    paginator = Paginator(qs, 25) 
    page = request.GET.get('page') 
    try: 
     pub = paginator.page(page) 
    except PageNotAnInteger: 
     pub = paginator.page(1) 
    except EmptyPage: 
     pub = paginator.page(paginator.num_pages) 
    url_filter = PublicationFilter(request.GET, queryset=qs) 
    return render(request, 'ingester/search_list.html', {'filter': url_filter, 'publication':pub}) 

Answer 1

我了解你的目标是你的分页过滤查询集。如果是这样，你可以通过 “QS” PublicationFilter对象的属性来分页程序构造：

def search(request): 
    qs = local_url.objects.filter(global_url__id=1).all() 
    url_filter = PublicationFilter(request.GET, queryset=qs) 
    paginator = Paginator(url_filter.qs, 25) 
    page = request.GET.get('page') 
    try: 
     pub = paginator.page(page) 
    except PageNotAnInteger: 
     pub = paginator.page(1) 
    except EmptyPage: 
     pub = paginator.page(paginator.num_pages) 
    url_filter = PublicationFilter(request.GET, queryset=qs) 
    return render(request, 'ingester/search_list.html', {'publication':pub}) 

url_filter.qs包含过滤查询集
url_filter.queryset包含非过滤查询集

Answer 2

要使用Django筛选和分页筛选结果，您可以执行以下操作：

1. 创建一个过滤器类模型：

   在my_project/my_app/filters.py：

   import django_filters 
   
   class MyModelFilter(django_filters.FilterSet): 
       class Meta: 
        model = MyModel 
        # Declare all your model fields by which you will filter 
        # your queryset here: 
        fields = ['field_1', 'field_2', ...] 
   

2. 每个FilterSet对象都有一个.qs属性，它包含了过滤的queryset，您甚至可以override it if you want。

3. 我们将分页我们MyModelFilter的.qs属性：

   在my_project/my_app/views.py：

   from . import filters 
   
   
   def my_view(request): 
       # BTW you do not need .all() after a .filter() 
       # local_url.objects.filter(global_url__id=1) will do 
       filtered_qs = filters.MyModelFilter(
            request.GET, 
            queryset=MyModel.objects.all() 
          ).qs 
       paginator = Paginator(filtered_qs, YOUR_PAGE_SIZE) 
   
       page = request.GET.get('page') 
       try: 
        response = paginator.page(page) 
       except PageNotAnInteger: 
        response = paginator.page(1) 
       except EmptyPage: 
        response = paginator.page(paginator.num_pages) 
   
       return render(
        request, 
        'your_template.html', 
        {'response': response} 
       ) 
   

有你有它！

---

PS_1： Django的过滤器在我的经验， "plays" better with Django Rest Framework。

PS_2：如果你要利用DRF，我已经写了关于如何在基于功能视图中使用分页的例子，你可以很容易地用FilterSet结合：

@api_view(['GET',]) 
def my_function_based_list_view(request): 
    paginator = PageNumberPagination() 
    filtered_set = filters.MyModelFilter(
         request.GET, 
         queryset=MyModel.objects.all() 
        ).qs 
    context = paginator.paginate_queryset(filtered_set, request) 
    serializer = MyModelSerializer(context, many=True) 
    return paginator.get_paginated_response(serializer.data)