如何使用Java标准API从字符串中获取特定数据？

Question

我有以下模式：

Jan(COMPANY) &^% Feb(ASP) 567 Mar(INC) 

我想最终的输出是：

String[] one = {"Jan", "Feb", "Mar"}; 
String[] two = {"COMPANY","ASP","INC"}; 

请帮助。任何人！！？

Answer 1

一个完整的例子，其存储String[] one和String[] two的结果是这样的：

import java.util.*; 
import java.util.regex.*; 

public class Main { 
    public static void main(String[] args) { 

     String str = "Jan(COMPANY) &^% Feb(ASP) 567 Mar(INC)"; 

     ArrayList<String> monthArr = new ArrayList<String>(); 
     ArrayList<String> dataArr = new ArrayList<String>(); 

     // Part 1: \\b(\\p{Alpha}+): Word boundary, one or more characters 
     // Part 2: \\(([^)]+)\\): "(", anything but ")" one or more times, ")" 
     Pattern p = Pattern.compile("\\b(\\p{Alpha}+)\\(([^)]+)\\)"); 
     Matcher m = p.matcher(str); 

     while (m.find()) { 
      monthArr.add(m.group(1)); // m.group(1) = "Jan", "Feb" and so on 
      dataArr.add(m.group(2)); // m.group(2) = "COMPANY, "ASP", and so on 
     } 

     String[] one = monthArr.toArray(new String[0]); 
     String[] two = dataArr.toArray(new String[0]); 
    } 
} 

Answer 2

迭代整个字符字符串和存储你所需要的。

String s = "Jan(COMPANY) &^% Feb(ASP) 567 Mar(INC)"; 

ArrayList<String> monthsList = new ArrayList<String>(); 
ArrayList<String> companyList = new ArrayList<String>(); 

StringBuilder b = new StringBuilder(); 
for (int i = 0; i < s.length(); i++) { 
    char c = s.charAt(i); 

    switch (c) { 

    case ' ': 
     b.setLength(0); 
     break; 
    case '(': 
     monthsList.add(b.toString()); 
     b.setLength(0); 
     break; 
    case ')': 
     companyList.add(b.toString()); 
     b.setLength(0); 
     break; 
    default: 
     b.append(c); 
     break; 
    } 
} 

String[] monthArray = monthsList.toArray(new String[] {}); 
String[] companyArray = companyList.toArray(new String[] {});