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如何将ActiveForm放到gridview列中?以下是我所做的代码:我试图渲染页面,使其包含我需要的活动窗体。把ActiveForm放在Gridview列中Yii2
'columns' => [
[ 'format' => 'html',
'value'=> function($data) { return Html::img($data->imageurl) . " <p class='feedback-username'>" . $data->username . "</p>"; },
'contentOptions'=>['style'=>'width: 30px; height: 30px'],
],
[ 'format' => 'raw',
'value' => function($model) { return "<p class='feedback'>". $model->KOMENTAR ."</p><br><p class='feedback-date'>". $model->TANGGAL ."</p><hr><div id='replay-". $model->ID_KOMENTAR."'><ul></ul></div>";},
],
[ 'format' => 'raw',
'contentOptions'=>['style'=>'width: 5px;'],
'value' => function($model) {
if($model->id == Yii::$app->user->identity->id) {
return Html::a('<i class="glyphicon glyphicon-share-alt"></i>',null,['id'=> 'replay-to-'. $model->ID_KOMENTAR ]).' '.
Html::a('<i class="glyphicon glyphicon-pencil"></i>', ['update', 'id' => $model->id]).' '.
Html::a('<i class="glyphicon glyphicon-trash"></i>', ['delete', 'id' => $model->id], ['data' => ['confirm' => 'Do you really want to delete this element?','method' => 'post']]);
}
return Html::a('<i class="glyphicon glyphicon-share-alt"></i>',['feedback', 'id' => $model->id],['id'=> 'replay-to-'. $model->ID_KOMENTAR ]);
},
],
[
'content' => $this->render('feedback_test'),
],
但我得到这个错误:
PHP Warning – yii\base\ErrorException
call_user_func() expects parameter 1 to be a valid callback, function '
<div class="feedback-form">
<p>test</p>
</div>' not found or invalid function name
怎样包括网格视图的列中的活性形式?
确定这就是很好的答案 –