试图创建自定义折线图,其中只有一条简单线条,带有渐变背景 - 线条各部分的背景根据在那点(数值的变化保证是温和的)。在D3.js中创建自定义折线图
我遇到了基本配置问题。这是我的代码:
JS:
// General definitions
var HEIGHT, MARGINS, WIDTH, formatDay, lineFunc, graph, graph_data, weekdays, x, xAxis, y, yAxis;
WIDTH = 360;
HEIGHT = 130;
MARGINS = {
top: 20,
right: 30,
bottom: 20,
left: 20
};
graph = d3.select("#graph");
// Define Axes
weekdays = ["MON", "TUE", "WED", "THU", "FRI", "SAT", "SUN"];
formatDay = function(d) {
return weekdays[d % 6];
};
x = d3.scale.linear().range([MARGINS.left, WIDTH - MARGINS.right]).domain([
d3.min(graph_data, function(d) {
return d.x;
}), d3.max(graph_data, function(d) {
return d.x + 1;
})
]);
y = d3.scale.linear().range([HEIGHT - MARGINS.top, MARGINS.bottom]).domain([
d3.min(graph_data, function(d) {
return d.y;
}), d3.max(graph_data, function(d) {
return d.y;
})
]);
xAxis = d3.svg.axis().scale(x).orient("bottom").tickFormat(formatDay);
yAxis = d3.svg.axis().scale(y).tickSize(10).orient("left");
// Line Function
lineFunc = d3.svg.line().x(function(d) {
return x(d.x);
}).y(function(d) {
return y(d.y);
}).interpolate("basis");
// Define Line Gradient
graph.append("linearGradient").attr("id", "line-gradient").attr("gradientUnits", "userSpaceOnUse").attr("x1", 0).attr("y1", y(0)).attr("x2", 0).attr("y2", y(200)).selectAll("stop").data([
{
offset: "0%",
color: "#F0A794"
}, {
offset: "20%",
color: "#F0A794"
}, {
offset: "20%",
color: "#E6A36A"
}, {
offset: "40%",
color: "#E6A36A"
}, {
offset: "40%",
color: "#CE9BD2"
}, {
offset: "62%",
color: "#CE9BD2"
}, {
offset: "62%",
color: "#AA96EE"
}, {
offset: "82%",
color: "#AA96EE"
}, {
offset: "82%",
color: "#689BE7"
}, {
offset: "90%",
color: "#689BE7"
}, {
offset: "90%",
color: "1AA1DF"
}, {
offset: "100%",
color: "1AA1DF"
}
]).enter().append("stop").attr("offset", function(d) {
return d.offset;
}).attr("stop-color", function(d) {
return d.color;
});
// Draw Line
graph.append("svg:path").attr("d", lineFunc(graph_data));
// Draw Axes
graph.append("svg:g").attr("class", "x axis").attr("transform", "translate(0," + (HEIGHT - MARGINS.bottom) + ")").call(xAxis);
graph.append("svg:g").attr("class", "y axis").attr("transform", "translate(" + MARGINS.left + ",0)").call(yAxis);
风格
#line-gradient {
fill: none;
stroke: url(#line-gradient);
stroke-width: 7px;
stroke-linejoin: "round";
}
的样本数据
graph_data = [{
x: 1,
y: 22
}, {
x: 2,
y: 20
}, {
x: 3,
y: 10
}, {
x: 4,
y: 40
}, {
x: 5,
y: 5
}, {
x: 6,
y: 30
}, {
x: 7,
y: 60
}]
什么我得到这个样子的:
任你D3.js高手能告诉我我在做什么错了,有什么需要,以改变我的线是一条线,而不是一个区域,具有上面解释的线条背景渐变和圆边?
非常感谢提前!
使之成为线可见,你需要给'path'生成行none'的''一和fill'适当'中风width'和' stroke'。 – 2014-11-23 18:48:43