算术上datetime对象

Question

http://docs.python.org/2/library/datetime.html

我用的是今天来获取当前的日期，如何将这些对象进行简单的算术，这样我可以减少或1或2（即昨天还是day-增加当前日期前天）

Answer 1

，你可以做以下

In [6]: import datetime 

# Today 
In [7]: datetime.datetime.now() 
Out[7]: datetime.datetime(2013, 1, 15, 15, 31, 10, 760000) 

# Tomorrow's date 
In [8]: print datetime.datetime.now() + datetime.timedelta(days=1) 
2013-01-16 15:31:15.336000 

# Day after tomorrow's day 
In [9]: print datetime.datetime.now() + datetime.timedelta(days=2) 
2013-01-17 15:31:52.601000 

# Yesterday's date 
In [10]: print datetime.datetime.now() - datetime.timedelta(days=1) 
2013-01-14 15:32:00.081000 

还与datetime.datetime.today（）

In [15]: datetime.datetime.today() 
Out[15]: datetime.datetime(2013, 1, 15, 15, 34, 37, 55000) 

In [16]: datetime.datetime.today() + datetime.timedelta(days=1) 
Out[16]: datetime.datetime(2013, 1, 16, 15, 34, 47, 560000)