ZIP的所有文件目录和下载的.zip产生

Question

嗯，首先，这是我的文件夹结构：

images/ 

image1.png 
image11.png 
image111.png 
image223.png 
generate_zip.php 

这是我generate_zip.php：

<?php 

    $files = array($listfiles); 

    $zipname = 'adcs.zip'; 
    $zip = new ZipArchive; 
    $zip->open($zipname, ZipArchive::CREATE); 
    foreach ($files as $file) { 
     $zip->addFile($file); 
    } 
    $zip->close(); 

    header('Content-Type: application/zip'); 
    header("Content-Disposition: attachment; filename='adcs.zip'"); 
    header('Content-Length: ' . filesize($zipname)); 
    header("Location: adcs.zip"); 

    ?> 

如何收集所有来自“images /”文件夹的文件，除了“generate_zip.php”，并使其可下载.zip？在这种情况下，“images /”文件夹总是有不同的图像。那可能吗？

Answer 1

这将确保PHP扩展文件不会被添加：

foreach ($files as $file) { 
     if(!strstr($file,'.php')) $zip->addFile($file); 
    } 

编辑：这里是完整的代码重写：

<?php 

    $zipname = 'adcs.zip'; 
    $zip = new ZipArchive; 
    $zip->open($zipname, ZipArchive::CREATE); 
    if ($handle = opendir('.')) { 
     while (false !== ($entry = readdir($handle))) { 
     if ($entry != "." && $entry != ".." && !strstr($entry,'.php')) { 
      $zip->addFile($entry); 
     } 
     } 
     closedir($handle); 
    } 

    $zip->close(); 

    header('Content-Type: application/zip'); 
    header("Content-Disposition: attachment; filename='adcs.zip'"); 
    header('Content-Length: ' . filesize($zipname)); 
    header("Location: adcs.zip"); 

    ?> 

Answer 2

改变你的foreach循环这个以除外generate_zip.php

foreach ($files as $file) { 
    if($file != "generate_zip.php"){ 
     $zip->addFile($file); 
    } 
} 

Answer 3

由于您只需要从某个目录创建Z的特定文件ipArchive你可以使用glob()函数来做到这一点。

<?php 
    $zip = new ZipArchive; 
    $download = 'download.zip'; 
    $zip->open($download, ZipArchive::CREATE); 
    foreach (glob("images/*.png") as $file) { /* Add appropriate path to read content of zip */ 
     $zip->addFile($file); 
    } 
    $zip->close(); 
    header('Content-Type: application/zip'); 
    header("Content-Disposition: attachment; filename = $download"); 
    header('Content-Length: ' . filesize($download)); 
    header("Location: $download"); 
?> 

不要使用水珠（），如果你尝试列出目录中的文件，其中很多文件存储（超过100.000）。您会收到“允许的内存大小XYZ字节耗尽...”错误。

readdir()是比较稳定的方式。 ！

Answer 4

=======工作液======

包括所有子文件夹：

<?php 
$the_folder = 'path/foldername'; 
$zip_file_name = 'archived_name.zip'; 

class FlxZipArchive extends ZipArchive { 
     /** Add a Dir with Files and Subdirs to the archive;;;;; @param string $location Real Location;;;; @param string $name Name in Archive;;; @author Nicolas Heimann;;;; @access private **/ 
    public function addDir($location, $name) { 
     $this->addEmptyDir($name); 
     $this->addDirDo($location, $name); 
    } // EO addDir; 

     /** Add Files & Dirs to archive;;;; @param string $location Real Location; @param string $name Name in Archive;;;;;; @author Nicolas Heimann * @access private **/ 
    private function addDirDo($location, $name) { 
     $name .= '/';   $location .= '/'; 
     // Read all Files in Dir 
     $dir = opendir ($location); 
     while ($file = readdir($dir)) { 
      if ($file == '.' || $file == '..') continue; 
      // Rekursiv, If dir: FlxZipArchive::addDir(), else ::File(); 
      $do = (filetype($location . $file) == 'dir') ? 'addDir' : 'addFile'; 
      $this->$do($location . $file, $name . $file); 
     } 
    } 
} 

$za = new FlxZipArchive; 
$res = $za->open($zip_file_name, ZipArchive::CREATE); 
if($res === TRUE) { 
    $za->addDir($the_folder, basename($the_folder)); $za->close(); 
} 
else { echo 'Could not create a zip archive';} 
?>