PostgreSQL函数

Question

这些都是提供给我

create type IR as (pattern_number integer, uoc_number integer); 

我目前正在进行的类型定义为：

create or replace function q1(pattern text, uoc_threshold integer) 
    returns setof IR 
    as $$ 
    BEGIN 
    RETURN QUERY 
    select count(code) from temp where code like $1; 
    RETURN QUERY 
    select count(code) from temp where code like $1 and uoc > $2; 

    END; 
$$ language plpgsql; 

我的输出要求是这样的： 查询： -

select * 
from q1('ECO%', 6); 

pattern_number | uoc_number 
80    |   5  

我收到一条错误消息：

ERROR: structure of query does not match function result type
DETAIL: Returned type bigint does not match expected type integer in column 1.
CONTEXT: PL/pgSQL function q1(text,integer) line 3 at RETURN QUERY

我该如何解决这个问题？

Answer 1

难道你想要什么？..

create or replace function q1(pattern text, uoc_threshold integer) 
    returns setof IR 
    as $$ 
    BEGIN 
    RETURN QUERY 
    select (select count(code) from temp where code like $1)::integer 
    ,(
    select count(code) from temp where code like $1 and uoc > $2)::integer; 

    END; 
$$ language plpgsql;