从日期时间列创建两列

所以我有一个关于从日期时间列创建两列的问题。从日期时间列创建两列

我的例子

CREATE TABLE #Test (ID int, OK bit, Data datetime) 
INSERT INTO #Test VALUES (1,0,'Dec 1 2015 12:00AM') 
INSERT INTO #Test VALUES (2,1,'Dec 2 2015 12:00AM') 
INSERT INTO #Test VALUES (3,1,'Dec 3 2015 12:00AM') 
INSERT INTO #Test VALUES (4,1,'Dec 4 2015 12:00AM') 
INSERT INTO #Test VALUES (5,0,'Dec 5 2015 12:00AM') 
INSERT INTO #Test VALUES (6,0,'Dec 6 2015 12:00AM') 
INSERT INTO #Test VALUES (7,1,'Dec 7 2015 12:00AM') 
INSERT INTO #Test VALUES (8,1,'Dec 8 2015 12:00AM') 
INSERT INTO #Test VALUES (9,1,'Dec 9 2015 12:00AM') 
INSERT INTO #Test VALUES (10,1,'Dec 10 2015 12:00AM') 
INSERT INTO #Test VALUES (11,1,'Dec 11 2015 12:00AM') 
INSERT INTO #Test VALUES (12,0,'Dec 12 2015 12:00AM') 
INSERT INTO #Test VALUES (13,0,'Dec 13 2015 12:00AM') 
INSERT INTO #Test VALUES (14,1,'Dec 14 2015 12:00AM') 
INSERT INTO #Test VALUES (15,1,'Dec 15 2015 12:00AM') 
INSERT INTO #Test VALUES (16,1,'Dec 16 2015 12:00AM') 
INSERT INTO #Test VALUES (17,1,'Dec 17 2015 12:00AM') 
INSERT INTO #Test VALUES (18,1,'Dec 18 2015 12:00AM') 
INSERT INTO #Test VALUES (19,0,'Dec 19 2015 12:00AM') 
INSERT INTO #Test VALUES (20,0,'Dec 20 2015 12:00AM') 
INSERT INTO #Test VALUES (21,1,'Dec 21 2015 12:00AM') 
INSERT INTO #Test VALUES (22,1,'Dec 22 2015 12:00AM') 
INSERT INTO #Test VALUES (23,1,'Dec 23 2015 12:00AM') 
INSERT INTO #Test VALUES (24,1,'Dec 24 2015 12:00AM') 
INSERT INTO #Test VALUES (25,0,'Dec 25 2015 12:00AM') 
INSERT INTO #Test VALUES (26,0,'Dec 26 2015 12:00AM') 
INSERT INTO #Test VALUES (27,0,'Dec 27 2015 12:00AM') 
INSERT INTO #Test VALUES (28,1,'Dec 28 2015 12:00AM') 
INSERT INTO #Test VALUES (29,1,'Dec 29 2015 12:00AM') 
INSERT INTO #Test VALUES (30,1,'Dec 30 2015 12:00AM')

即产生以下结果

ID OK Data 
-------------------- 
1 0 2015-12-01 00:00:00.000 
2 1 2015-12-02 00:00:00.000 
3 1 2015-12-03 00:00:00.000 
4 1 2015-12-04 00:00:00.000 
5 0 2015-12-05 00:00:00.000 
6 0 2015-12-06 00:00:00.000 
7 1 2015-12-07 00:00:00.000 
8 1 2015-12-08 00:00:00.000 
9 1 2015-12-09 00:00:00.000 
10 1 2015-12-10 00:00:00.000 
11 1 2015-12-11 00:00:00.000 
12 0 2015-12-12 00:00:00.000 
13 0 2015-12-13 00:00:00.000 
14 1 2015-12-14 00:00:00.000 
15 1 2015-12-15 00:00:00.000 
16 1 2015-12-16 00:00:00.000 
17 1 2015-12-17 00:00:00.000 
18 1 2015-12-18 00:00:00.000 
19 0 2015-12-19 00:00:00.000 
20 0 2015-12-20 00:00:00.000 
21 1 2015-12-21 00:00:00.000 
22 1 2015-12-22 00:00:00.000 
23 1 2015-12-23 00:00:00.000 
24 1 2015-12-24 00:00:00.000 
25 0 2015-12-25 00:00:00.000 
26 0 2015-12-26 00:00:00.000 
27 0 2015-12-27 00:00:00.000 
28 1 2015-12-28 00:00:00.000 
29 1 2015-12-29 00:00:00.000 
30 1 2015-12-30 00:00:00.000

所以我的问题是我怎么能不使用光标或同时创建一个两列的表。

输出应该是。我知道我可以通过使用游标来实现这一点，但它必须是一个更简单的方法。任何帮助？

StartDate     EndDate 
    ----------------------- ----------------------- 
    2015-12-02 00:00:00.000 - 2015-12-04 00:00:00.000 
    2015-12-07 00:00:00.000 - 2015-12-11 00:00:00.000 
    2015-12-14 00:00:00.000 - 2015-12-18 00:00:00.000 
    2015-12-21 00:00:00.000 - 2015-12-24 00:00:00.000 
    2015-12-28 00:00:00.000 - 2015-12-30 00:00:00.000

来源

2015-12-18 CiucaS

是你的问题如何与查询做到这一点，因为当你说“创建一个两列的表”，那么你可以只做到这一点，而不是单一的一个？如果查询 - 使用什么逻辑？ –

是的，我想在查询中做到这一点。 – CiucaS

您可以使用下面的查询：

SELECT MIN(Data) AS StartDate, 
     MAX(Data) AS EndDate 
FROM (
    SELECT ID, OK, Data, 
     DATEADD(d, -1 * ROW_NUMBER() OVER 
         (PARTITION BY OK ORDER BY ID), Data) AS grp 
    FROM Test) AS t 
WHERE OK = 1 
GROUP BY grp

查询使用计算字段grp识别具有连续日期withing相同OK片连续记录的岛屿。

Demo here

来源

2015-12-18 07:38:51

谢谢！这是我正在寻找的。 – CiucaS

从日期时间列创建两列

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