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创建foreach循环阵列我有一个形式与表是这样的:JavaScript的 - 通过表
<table id="preview">
<tbody>
<tr>
<td>01/01/2010</td>
<td>Credit</td>
<td>1000</td>
</tr>
<tr>
<td>01/05/2010</td>
<td>Debit</td>
<td>200</td>
</tr>
<tr>
<td>01/09/2010</td>
<td>Debit</td>
<td>400</td>
</tr>
<tr>
<td>01/11/2010</td>
<td>Debit</td>
<td>100</td>
</tr>
</tbody>
</table>
现在我需要建立一个数组来发送(AJAX/PHP)是这样的:
$ajaxArray = array( 0 => array(From => "01/01/2010", //1st td of the 1st Row
To => "01/05/2010", //1st td of the 2nd Row
Type => "Credit",
Amount => 1000.00),
1 => array(From => "01/05/2010", //1st td of the 2nd Row
To => "01/09/2010", //1st td of the 3th Row
Type => "Debit",
Amount => 200.00),
2 => array(From => "01/09/2010", //1st td of the 3th Row
To => "01/11/2010", //1st td of the 4th Row
Type => "Debit",
Amount => 400.00),
3 => array(From => "01/11/2010", //1st td of the 4th Row
To => "01/01/2012", //Value in $last_date var
Type => "Debit",
Amount => 100.00)
);
我试着用这个代码:
$('#preview > tbody > tr').each(function() {
var from = $('td:eq(0) ', this).text();
var type = $('td:eq(1) ', this).text();
var amount = $('td:eq(2) ', this).text();
ajaxArray.push({
From: from,
Type: type,
Amount: amount
});
});
正如你可以看到我不能让“到”日期值。 “To”日期值是除最后一行以外的下一行的第一个TD中包含的日期,其中此值位于$ last_date变量中。
在此先感谢
非常感谢。除了最后一个数组外,这段代码对每一行都是完美的。如何从$ last_date变量获取最后一个日期? – fasenderos
我不知道,没有经验的PHP对不起。 – Hatsjoem
好的没问题。我可以通过添加最后一个“To”日期的隐藏行来解决问题。 – fasenderos