我正在开发一个android应用程序,在每次活动中,我需要将一些数据传递到服务器上,并在进入下一个活动之前取回响应。如果互联网足够快,应用程序就可以正常工作。但随着速度的降低,应用程序部队将关闭。如何处理缓慢的互联网连接,以便它可能不会导致强制关闭应用程序?????缓慢的互联网连接导致部队关闭
这里是代码
public void onClick(View v) {
// TODO Auto-generated method stub
UserFunctions userFunction = new UserFunctions();
if(userFunction.isNetworkAvailable(getApplicationContext()))
{
answer="";
for(int check1=0;check1<counter2;check1++){
int check2=0;
answer=answer+option4[check1]+"|";
while(check2<counter1){
if(edTxt[check1][check2].getText().toString().equals("")){
answer="";
break;
}
else{
answer=answer+edTxt[check1][check2].getText().toString()+"|";
}
check2++;
}
if(answer.equals("")){
break;
}
else{
answer=answer+"||";
}
}
if(answer.equals("")){
Toast.makeText(this, "Please fill all fields", 600).show();
}
else{
userFunction.form1(surveyId,userId , quesNo, answer);
if(total>0){
draw(temp);
}
else{
ques_no++;
ArrayList<NameValuePair> params = new ArrayList<NameValuePair>();
params.add(new BasicNameValuePair("quesNo", Integer.toString(ques_no)));
params.add(new BasicNameValuePair("surveyId", surveyId));
count = getJsonFromURL22(surveyCond, params);
j=Integer.parseInt(result);
if(j==22)
{
Toast.makeText(this, "Survey Completed", 600).show();
Intent home=new Intent(Format16.this, SurveyCompleted.class);
UserFunctions userFunctions = new UserFunctions();
userFunctions.full(surveyId);
Bundle d=new Bundle();
d.putString("userId", userId);
home.putExtras(d);
startActivity(home);
}
public String getJsonFromURL22(String url, List<NameValuePair> params){
try{
HttpClient httpclient = new DefaultHttpClient();
HttpPost httppost = new HttpPost(url);
httppost.setEntity(new UrlEncodedFormEntity(params));
HttpResponse response = httpclient.execute(httppost);
HttpEntity entity = response.getEntity();
is = entity.getContent();
}catch(Exception e){
Log.e("log_tag", "Error in http connection"+e.toString());
}
//convert response to string
try{
BufferedReader reader = new BufferedReader(new InputStreamReader(is,"iso-8859-1"),8);
sb = new StringBuilder();
sb.append(reader.readLine());
String line="0";
while ((line = reader.readLine()) != null) {
sb.append(line);
}
is.close();
result=sb.toString();
}catch(Exception e){
Log.e("log_tag", "Error converting result "+e.toString());
}
return result;
}
向我们展示一些代码。还有logcat错误。 – Rajesh
你正在做网络在不同的线程继续吧? –
你应该看看这个链接: http://stackoverflow.com/questions/11150583/if-an-activity-takes-long-time-to-load-it-asks-for-force-close-如何对解决次/ 11150845#11150845 –