XML VS JSON第一
,如果你要使用API来执行一些AJAX查询(比如,查询API当用户点击一个链接/图像,例如,你想改变该链接的颜色,女巫会告诉用户它是好的或不是...去JSON,因为你不需要解析XML)
如果你在做任何事情“灌木丛”,你只需要呈现在后面的代码中处理的数据,然后使用XML。
简单使用,在这个时候WebClient的对象
private string GetDocument(string myPin) {
String url = String.Format("http://someservice.com/name_query.php?pincode={0}", myPin);
WebClient client = new WebClient();
client.Headers.Add("user-agent", "Mozilla/4.0 (compatible; MSIE 7.0; Windows NT 6.0;)"); // pass as Internet Explorer 7.0
Stream data = client.OpenRead(url);
StreamReader reader = new StreamReader(data);
s = reader.ReadToEnd();
data.Close();
reader.Close();
return s;
}
,你有你在一个字符串的API得到了完整的XML,你现在需要的是处理XML,例如,如:
想象的输出是等的XML文档:
<Hit dbId="400179221" systemId="115">
<WorksiteDbId>200105072</WorksiteDbId>
<Subscribed>false</Subscribed>
<FirstName>Klaus Holse</FirstName>
<LastName>Andersen</LastName>
<Status>Active</Status>
<MainJobTitle>CEO (Managing Director, General Manager, Owner)</MainJobTitle>
<WorksiteName>Microsoft Development Center Copenhagen ApS </WorksiteName>
<Department></Department>
<Address></Address>
<Zipcode></Zipcode>
<City></City>
<WorksitePhone></WorksitePhone>
<TypeCode>TY10</TypeCode>
<WorksiteStatus>Active</WorksiteStatus>
</Hit>
的方法来处理文档信息是这样的:
private void processDocument(string myPin) {
String xml = GetDocument(myPin);
XmlTextReader reader = new XmlTextReader(new StringReader(xml));
XmlDocument document = new XmlDocument();
document.Load(reader);
XmlNodeList list = document.SelectNodes("/XMLNode/XMLSubNode");
foreach (XmlNode node in list) // loop through all nodes
{
foreach (XmlAttribute att in node.Attributes) // loop through all attributes
{
switch (att.Name.ToLower())
{
case "dbid": myClass.DbID = Int32.Parse(att.InnerText); break;
case "systemid": myClass.SystemID = Int32.Parse(att.InnerText); break;
default: break;
}
}
foreach (XmlNode subnode in node.ChildNodes) // loop through all subnodes
{
switch (subnode.Name.ToLower()) // check what node has what
{
case "subscribed": myClass.Subscribed = bool.Parse(subnode.InnerText); break;
case "firstname": myClass.Firstname = subnode.InnerText; break;
case "lastname": myClass.Lastname = subnode.InnerText; break;
case "status": myClass.Status = subnode.InnerText; break;
...
}
}
}
}
,你将有myClass的充满了由API所返回的所有值...
为您在第一线提...这是新手:)和这是一个很好的方式来了解获取和使用XML数据的概念...在了解了这部分之后,然后您将轻松移动到LINQ2XML :)
我希望这有助于...
添加
,因为我现在才看到你的XML的输出,这里是使用精确的XML
XML的processDocument方法:
<?xml version="1.0" encoding="UTF-8"?>
<Address>
<Country>US</Country>
<City>Seattle</City>
<Result>Done</Result>
</Address>
方法:
private void processDocument(string myPin) {
String xml = GetDocument(myPin);
XmlTextReader reader = new XmlTextReader(new StringReader(xml));
XmlDocument document = new XmlDocument();
document.Load(reader);
XmlNodeList list = document.SelectNodes("/Address");
foreach (XmlNode node in list) // loop through all nodes
{
foreach (XmlNode subnode in node.ChildNodes) // loop through all subnodes
{
switch (subnode.Name.ToLower()) // check what node has what
{
case "country": myClass.Country =subnode.InnerText; break;
case "city": myClass.City= subnode.InnerText; break;
case "result": myClass.Result = subnode.InnerText; break;
}
}
}
}
记得检查错误,比如传递一组错误的数据,以便正确处理错误。
:-)
谢谢david..how我可以从返回XML或JSON的url中获取xmlSourceString吗? – Musa 2009-05-26 12:15:20
您可以将变量xmlSourceString设置为从打开URL并按照balexandre描述的方式使用WebClient读取流时返回的XML。 – 2009-05-26 12:22:17