2012-03-12 70 views
2

我在下面写了两个查询,每个查询产生一行数据。水平连接两个查询

什么是最好的方式来组合它们,使我只有一行数据的LEFT

这些都是未来 databases命名:ASN01]和[dsi_ASN_dsicx]

我70对这样的数据库,但我只显示一个简单性。

三字母首字母缩写词ASN在两个数据库名称中都是通用的这一事实没有错,如果需要可以成为解决方案的一部分。

当前结果:

网站,Elligence(标题) ASN,100.00

网站,GP_Total(标题) ASN,120.00

期望的结果:

网站,GP_Total, Elligence(header) ASN,120.00,100.00

SELECT 'ASN' AS Site , 
     CASE SUM(perdblnc) 
      WHEN NULL THEN 0 
      ELSE -1 * SUM(PERDBLNC) 
     END AS GP_Total 
FROM [ASN01].[dbo].[GL10110] T1 
     LEFT OUTER JOIN [ASN01].[dbo].[GL00105] T2 ON [T1].[ACTINDX] = [T2].[ACTINDX] 
WHERE YEAR1 = 2012 
     AND PERIODID IN ('2') 
     AND ACTNUMST IN ('4200-0000-C', '6940-0000-C', '6945-0000-C', 
          '6950-0000-C') 

SELECT 'ASN' AS [Site] , 
     SUM(pi.amount) AS [Elligence] 
FROM [dsi_ASN_dsicx].dbo.charge c 
     LEFT JOIN [dsi_ASN_dsicx].dbo.paymentitem pi ON c.idcharge = pi.chargeid 
     LEFT JOIN [dsi_ASN_dsicx].dbo.payment p ON pi.paymentid = p.idpayment 
     LEFT JOIN [dsi_ASN_dsicx].dbo.paymenttype pt ON p.paymenttypeid = pt.idpaymenttype 
WHERE pi.amount != 0 
     AND pt.paymentmethod NOT IN ('5', '7') 
     AND pt.paymentmethod IS NOT NULL 
     AND p.sdate >= '20120201' 
     AND p.sdate <= '20120229' 
+0

这看起来像两组不同的数据。什么定义了一个共同的行?这些查询甚至产生相同数量的行吗? – Paparazzi 2012-03-13 00:10:17

+0

它在帖子中说,他只收到每个查询@Blam的一行。他希望他们加入一行。 – ImGreg 2012-03-13 02:36:47

回答

5

无需通过并更改任何查询,最简单的方法就是使用"WITH" common_table_expression来使用临时表。表1和表2是从您的select语句创建的临时表。因此,我们选择table1并连接table2。

让我知道是否有任何语法问题,目前我没有任何测试。

;With Table1 as (SELECT 'ASN' as Site, Case sum(perdblnc) 
WHEN NULL THEN 0 
ELSE -1*sum(PERDBLNC) END as GP_Total 
FROM [ASN01].[dbo].[GL10110] T1 
Left Outer Join [ASN01].[dbo].[GL00105] T2 
ON [T1]. [ACTINDX]= [T2]. [ACTINDX] 
WHERE YEAR1 = 2012 
AND PERIODID in ('2') 
AND ACTNUMST in ('4200-0000-C', '6940-0000-C', '6945-0000-C', '6950-0000-C')) 

, Table2 as (SELECT 
    'ASN' as [Site], 
    SUM(pi.amount) as [Elligence] 
FROM [dsi_ASN_dsicx].dbo.charge c 
    LEFT JOIN [dsi_ASN_dsicx].dbo.paymentitem pi on c.idcharge = pi.chargeid 
    LEFT JOIN [dsi_ASN_dsicx].dbo.payment p on pi.paymentid = p.idpayment 
    LEFT JOIN [dsi_ASN_dsicx].dbo.paymenttype pt on p.paymenttypeid = pt.idpaymenttype 
WHERE pi.amount != 0 
AND pt.paymentmethod not in ('5','7') 
AND pt.paymentmethod is not null 
AND p.sdate >='20120201' and p.sdate <= '20120229') 

SELECT * FROM Table1 
LEFT JOIN Table2 ON Table1.site = Table2.site 

希望这会有所帮助!标记为答案,如果它=)

+1

+1用于回答一个非常不同的问题。我想也许它应该是一个完全的联合,我不知道是否有人可能缺席。你不需要最后的连接中的ON子句(ON Table1.site = Table2.site)? – 2012-03-13 02:56:20

+0

谢谢@LevinMagruder。我将编辑以包含ON子句。 – ImGreg 2012-03-13 03:30:05

+1

这个解决方案完美无瑕!语法对于MS SSMS来说是完美的。非常感谢帮助。 – MSS 2012-03-13 18:40:34