只有一个数组返回，我期待Ruby中的数组数组

Question

当我在irb中运行以下内容时，它将返回我想要的内容。但是当我运行rspec -c intersection_spec.rb时，它会返回[[0,0]]。为什么不用rspec获得期望的结果？

我在这里做错了什么？

intersection.rb

class Intersection 

    def self.create_arr(xa1, ya1, xa2, ya2) 
    ((xa1.to_i)..(xa2.to_i)).to_a.product(((ya1.to_i)..(ya2.to_i)).to_a) 
    end 

end 

intersection_spec.rb

require './spec_helper' 
require './intersection.rb' 

describe Intersection do 

    @xa1 = 0.0 
    @ya1 = 0.0 
    @xa2 = 5.0 
    @ya2 = 5.0 
    @xb1 = 1.0 
    @yb1 = 1.0 
    @xb2 = 4.0 
    @yb2 = 4.0 

    specify{ expect(Intersection.create_arr(@xa1, @ya1, @xa2, @ya2)).to eq [[0,0], 
[0,1], [0,2], [0,3], [0,4], [0,5], [1,0], [1,1], [1,2], [1,3], [1,4], [1,5], 
[2,0], [2,1], [2,2], [2,3], [2,4], [2,5], [3,0], [3,1], [3,2], [3,3], [3,4], 
[3,5], [4,0], [4,1], [4,2], [4,3], [4,4], [4,5], [5,0], [5,1], [5,2], [5,3], 
[5,4], [5,5]] } 

end 

运行rspec的。

rspec -c intersection_spec.rb 

    expected: [[0, 0], [0, 1], [0, 2], [0, 3], [0, 4], [0, 5], [1, 0], [1, 1], 
[1, 2], [1, 3], [1, 4], [1, 5], [2, 0], [2, 1], [2, 2], [2, 3], [2, 4], [2, 5], 
[3, 0], [3, 1], [3, 2], [3, 3], [3, 4], [3, 5], [4, 0], [4, 1], [4, 2], [4, 3], 
[4, 4], [4, 5], [5, 0], [5, 1], [5, 2], [5, 3], [5, 4], [5, 5]] 
got: [[0, 0]] 

在IRB

irb(main):029:0> @xa1 = 0.0 
=> 0.0 
irb(main):030:0> @ya1 = 0.0 
=> 0.0 
irb(main):031:0> @xa2 = 5.0 
=> 5.0 
irb(main):032:0> @ya2 = 5.0 
=> 5.0 
irb(main):033:0> @xb1 = 1.0 
=> 1.0 
irb(main):034:0> @yb1 = 1.0 
=> 1.0 
irb(main):035:0> @xb2 = 4.0 
=> 4.0 
irb(main):036:0> @yb2 = 4.0 
=> 4.0 
irb(main):037:0> def self.create_arr(xa1, ya1, xa2, ya2) 
irb(main):038:1>  ((xa1.to_i)..(xa2.to_i)).to_a.product(((ya1.to_i)..(ya2.to_i)).to_a) 
irb(main):039:1> end 
=> nil 
irb(main):040:0> create_arr(@xa1, @ya1, @xa2, @ya2) 
=> [[0, 0], [0, 1], [0, 2], [0, 3], [0, 4], [0, 5], [1, 0], [1, 1], [1, 2], 
[1, 3], [1, 4], [1, 5], [2, 0], [2, 1], [2, 2], [2, 3], [2, 4], [2, 5], [3, 0], 
[3, 1], [3, 2], [3, 3], [3, 4], [3, 5], [4, 0], [4, 1], [4, 2], [4, 3], [4, 4], 
[4, 5], [5, 0], [5, 1], [5, 2], [5, 3], [5, 4], [5, 5]] 

Answer 1

我不能肯定地说，失败的原因你的方式，但我注意到它的工作，当你不把初始坐标实例变量，所以

@xa1 = 0.0 
    @ya1 = 0.0 
    @xa2 = 5.0 
    @ya2 = 5.0 

成为

xa1 = 0.0 
    ya1 = 0.0 
    xa2 = 5.0 
    ya2 = 5.0 

然后将这些传递给#create_array。