2012-08-07 61 views
2

我有一个创建发票的表单,发送方和接收方表单输入取自数据库中的可用列表。用于表单输入选项的CakePHP自定义标签

accounts(id,...., company_name, abn) ---> id is primary 
users(id, username, title, firstname, surname,...) ---> id is primary 
accounts_users(id, account_id, user_id) --->account_id from accounts, user_id from users 

每个用户只能属于一个帐户,但一个帐户可以有多个用户。 根据登录用户的身份,表单输入是account_id。

在发票控制器:

$accounts3=$this->User->AccountsUser->find('list', array(
     'fields'=>array('account_id','account_id'),'conditions' => array(
     'user_id' => $this->Auth->user('id')))); 


$accounts=$this->User->Relationship->find('list', array('fields'=>array('receiver_id'),'conditions' => array('sender_id' => $accounts2))); 

在addInvoice视图:

<?php 
echo $this->Form->create('Invoice', array('action'=>'addinvoice')); 
echo $this->Form->input('sender_id',array('label'=>'Sender: ', 'options' => array('$accounts3' => 'COMPANY NAME'))); 
echo $this->Form->input('receiver_id',array('label'=>'Receiver: ', 'type' => 'select', 'options' => $accounts)); 
echo $this->Form->input('active', array('label' => 'Schedule?', 'options' => array('1'=>'Send','0'=>'Schedule'), 'default'=>'1')); 
echo $this->Form->hidden('templates_id', array('default'=>'0')); 
echo $this->Form->end('Submit'); 

“公司名称”的这种情况下的标签被硬编码,并且需要由动态标签来代替这将是accounts表中的company_name

比较复杂一点,接收器标签必须company_nameaccounts,或者如果company_nameNULL,(所以他们个人,而不是一个企业帐户),这将是从usersusername

解决方案尝试: ***在InvoicesController

$sendername=$this->User->Account->find('list', array('fields'=>array('company_name'),'conditions' => array('account_id' => $accounts3))); 

OR

$sendername=$this->User->AccountsUser->find('list', array('fields'=>array('id','company_name'),'conditions' => array('user_id' => $this->Auth->user('id')))); 

那些创造$sendername变量似乎不工作,不知道是否在CakePHP的甚至可能吗?

+0

我们改变了我们的数据库:1-M帐户给用户,因此不需要AccountsUser。我们还将company_name更改为account_name以获得数据库有效性。删除NULL,并且还为编码理智! :)解决了! – 2012-08-22 17:04:57

回答

0
$accounts3 = $this->User->AccountsUser->Account->find('list', array(
    'fields' => array('company_name'), 
    'joins' => array(
     array(
      'alias' => 'AccountsUser', 
      'table' => 'accounts_users', 
      'type' => 'left', 
      'conditions' => array('AccountsUser.account_id = Account.id'), 
     )  
    ), 
    'conditions' => array(
     'AccountsUser.user_id' => $this->Auth->user('id'), 
    ) 
)); 

// find all accounts with id => label from accounts table 
// where AccountsUser.user_id = id of logged in user 
// label being user.username when company_name is null or company_null if not null 
$this->User->AccountsUser->Account->virtualFields['label'] = 'CASE WHEN Account.company_name IS NULL THEN User.username ELSE Account.company_name END'; 
$accounts = $this->User->AccountsUser->Account->find('list', array(
    'fields' => array('label'), 
    'joins' => array(
     array(
      'alias' => 'AccountsUser', 
      'table' => 'accounts_users', 
      'type' => 'left', 
      'conditions' => array('AccountsUser.account_id = Account.id'), 
     ), 
     array(
      'alias' => 'User', 
      'table' => 'users', 
      'type' => 'left', 
      'conditions' => array('AccountsUser.user_id = User.id'), 
     ),  
    ), 
    'conditions' => array(
     'AccountsUser.user_id' => $this->Auth->user('id'), 
    ) 
)); 

不知道这是否是你想要的东西,如果我理解正确的问题,但希望它会给你的东西走下车的。

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