我有这样的代码来拉数据库中的数据并将数据插入到4列之一,这段代码可以更清洁吗?它看起来是正确的状态?
我花了一整天搜索,只是不能似乎找到了如何做到这一点..
理想情况下,我想选择所有的数据库,然后在获取数组有1列ID - 反响,那么大人了下一列等。
<?php
echo '<div class="column grid_3 clearfix" id="column0" >';
echo ' ';
$user_sites_0=mysqli_query($connection, "SELECT * FROM user_sites WHERE column_id='0' ORDER BY sort_no");
if(!$user_sites_0) {
echo 'No sites added, please <a class="addsite" href="#">add one now</a>';
}
else {
while($user_site_0=mysqli_fetch_array($user_sites_0))
{
$id = stripslashes($user_site_0['id']);
$site_name = stripslashes($user_site_0['site_name']);
$site_address = stripslashes($user_site_0['site_address']);
$site_desc = stripslashes($user_site_0['site_desc']);
$site_category = stripslashes($user_site_0['site_category']);
$getImage = 'http://immediatenet.com/t/s?Size=1024x768&URL='.$site_address;
echo '<div class="dragbox" id="item'.$id.'">';
echo '<h2 class="h2handle">'.$site_name.' <span class="close"><a href="#" id="'.$id.'" class="delete_button"><img src="assets/img/closepanel.png"></a></span></h2>';
echo '<div class="dragbox-content" ';
if($user_site_0['collapsed']==1)
echo 'style="display:none;" ';
echo '>';
echo '<p><a class="sitelink" href="' . $site_address . '" title="'.$site_name.'"><img src="'.$getImage.'" alt="'.$site_name.'" title="'.$site_name.'"/></a>';
echo '<p>' . $site_category . '</p>';
echo '<p>' . $site_address . '</p>';
echo '<p>' . $site_desc . '</p>';
echo' </div>
</div>';
}
}
echo '</div>';
?>
<?php
echo '<div class="column grid_3 clearfix" id="column1" >';
echo ' ';
$user_sites_1=mysqli_query($connection, "SELECT * FROM user_sites WHERE column_id='1' ORDER BY sort_no");
if(!$user_sites_1) {
echo '';
}
else {
while($user_site_1=mysqli_fetch_array($user_sites_1))
{
$id = stripslashes($user_site_1['id']);
$site_name = stripslashes($user_site_1['site_name']);
$site_address = stripslashes($user_site_1['site_address']);
$site_desc = stripslashes($user_site_1['site_desc']);
$site_category = stripslashes($user_site_1['site_category']);
$getImage = 'http://immediatenet.com/t/s?Size=1024x768&URL='.$site_address;
echo '<div class="dragbox" id="item'.$id.'">';
echo '<h2 class="h2handle">'.$site_name.' <span class="close"><a href="#" id="'.$id.'" class="delete_button"><img src="assets/img/closepanel.png"></a></span></h2>';
echo '<div class="dragbox-content" ';
if($user_site_1['collapsed']==1)
echo 'style="display:none;" ';
echo '>';
echo '<p><a class="sitelink" href="' . $site_address . '" title="'.$site_name.'"><img src="'.$getImage.'" alt="'.$site_name.'" title="'.$site_name.'"/></a>';
echo '<p>' . $site_category . '</p>';
echo '<p>' . $site_address . '</p>';
echo '<p>' . $site_desc . '</p>';
echo' </div>
</div>';
}
}
echo '</div>';
?>
<?php
echo '<div class="column grid_3 clearfix" id="column2">';
echo ' ';
$user_sites_2=mysqli_query($connection, "SELECT * FROM user_sites WHERE column_id='2' ORDER BY sort_no");
if(!$user_sites_2) {
echo '';
}
else {
while($user_site_2=mysqli_fetch_array($user_sites_2))
{
$id = stripslashes($user_site_2['id']);
$site_name = stripslashes($user_site_2['site_name']);
$site_address = stripslashes($user_site_2['site_address']);
$site_desc = stripslashes($user_site_2['site_desc']);
$site_category = stripslashes($user_site_2['site_category']);
$getImage = 'http://immediatenet.com/t/s?Size=1024x768&URL='.$site_address;
echo '<div class="dragbox" id="item'.$id.'">';
echo '<h2 class="h2handle">'.$site_name.' <span class="close"><a href="#" id="'.$id.'" class="delete_button"><img src="assets/img/closepanel.png"></a></span></h2>';
echo '<div class="dragbox-content" ';
if($user_site_2['collapsed']==1)
echo 'style="display:none;" ';
echo '>';
echo '<p><a class="sitelink" href="' . $site_address . '" title="'.$site_name.'"><img src="'.$getImage.'" alt="'.$site_name.'" title="'.$site_name.'"/></a>';
echo '<p>' . $site_category . '</p>';
echo '<p>' . $site_address . '</p>';
echo '<p>' . $site_desc . '</p>';
echo' </div>
</div>';
}
}
echo '</div>';
?>
<?php
echo '<div class="column grid_3 clearfix" id="column3">';
echo ' ';
$user_sites_3=mysqli_query($connection, "SELECT * FROM user_sites WHERE column_id='3' ORDER BY sort_no");
while($user_site_3=mysqli_fetch_array($user_sites_3))
{
$id = stripslashes($user_site_3['id']);
$site_name = stripslashes($user_site_3['site_name']);
$site_address = stripslashes($user_site_3['site_address']);
$site_desc = stripslashes($user_site_3['site_desc']);
$site_category = stripslashes($user_site_3['site_category']);
$getImage = 'http://immediatenet.com/t/s?Size=1024x768&URL='.$site_address;
echo '<div class="dragbox" id="item'.$id.'">';
echo '<h2 class="h2handle">'.$site_name.' <span class="close"><a href="#" id="'.$id.'" class="delete_button"><img src="assets/img/closepanel.png"></a></span></h2>';
echo '<div class="dragbox-content" ';
if($user_site_3['collapsed']==1)
echo 'style="display:none;" ';
echo '>';
echo '<p><a class="sitelink" href="' . $site_address . '" title="'.$site_name.'"><img src="'.$getImage.'" alt="'.$site_name.'" title="'.$site_name.'"/></a>';
echo '<p>' . $site_category . '</p>';
echo '<p>' . $site_address . '</p>';
echo '<p>' . $site_desc . '</p>';
echo' </div>
</div>';
}
echo '</div>';
?>
的代码看起来正确的状态..莫非我做得更好?
你要求的代码的改进?那么你应该使用http://codereview.stackexchange.com/。 – vstm
模板引擎从不会伤害任何人...一百万回声的效率会受到质疑,以及代码的可维护性。 – 2011-10-09 09:17:16
我正在考虑这个问题,但是想从头开始编码学习..我买不起uni所以使用2个最好的东西..谷歌和堆栈溢出:) –