计数日历周，并将它们存储到一个数组与.isocalendar

Question

，所以我得到一本字典，看起来像这样：

{2321: datetime.datetime(2015, 2, 16, 11, 55, 50, 414175, tzinfo=<LocalTimezone "UTC+01:00" 1:00:00>), 
2322: datetime.datetime(2015, 2, 16, 13, 10, 17, 338086, tzinfo=<LocalTimezone "UTC+01:00" 1:00:00>), 
2323: datetime.datetime(2015, 2, 16, 13, 12, 30, 847941, tzinfo=<LocalTimezone "UTC+01:00" 1:00:00>), 
2324: datetime.datetime(2015, 2, 16, 13, 15, 14, 803438, tzinfo=<LocalTimezone "UTC+01:00" 1:00:00>), 
2325: datetime.datetime(2015, 2, 16, 13, 17, 42, 749529, tzinfo=<LocalTimezone "UTC+01:00" 1:00:00>), 
2326: datetime.datetime(2015, 2, 16, 13, 19, 58, 757024, tzinfo=<LocalTimezone "UTC+01:00" 1:00:00>), 
2327: datetime.datetime(2015, 2, 16, 13, 22, 16, 554052, tzinfo=<LocalTimezone "UTC+01:00" 1:00:00>), 
2328: datetime.datetime(2015, 2, 16, 13, 26, 56, 4452, tzinfo=<LocalTimezone "UTC+01:00" 1:00:00>), 
2081: datetime.datetime(2015, 1, 27, 10, 28, 10, 695887, tzinfo=<LocalTimezone "UTC+01:00" 1:00:00>), 
2082: datetime.datetime(2015, 1, 27, 10, 35, 34, 71091, tzinfo=<LocalTimezone "UTC+01:00" 1:00:00>), 
2083: datetime.datetime(2015, 1, 27, 10, 40, 1, 436955, tzinfo=<LocalTimezone "UTC+01:00" 1:00:00>)} 

其{ticketID：ticketDateTime}

我想使用.isocalendar从DateTime对象中获取日历周期（因为我需要为每周计算门票）

我想过创建一个长度为52（因为一年有52周）的零填充数组，然后迭代带有forloop的字典，并且总是为索引o添加1 f这个日历周。

对不起，我在新的蟒蛇，并会尝试向你展示在C＃中的一些代码，我怎么想它可以工作：

int[] resultsArray = new int[52] 

for(int i = 0; i<= myDictionary.Length; i++){ 
index = myDictionary[i].isocalendar()[1] 
resultsArray[index] = resultsArray[index]+1} 

Answer 1

试试这个：

ClosedList = [0] * 53 
OpenList = [0] * 53 
OpenedList = [0] * 53 
def CreateKWlist(): 
for i in ClosedDict: 
    for j,k in ClosedDict[i]['prio-events']: 
     if j.isocalendar()[0] == 2015: 
      index = j.isocalendar()[1] 
      ClosedList[index] += 1 
      OpenedList[index] += 1 
      break 
for i in OpenDict: 
    for j,k in OpenDict[i]['prio-events']: 
     if j.isocalendar()[0] == 2015: 
      index = j.isocalendar()[1] 
      OpenList[index] += 1 
      OpenedList[index] += 1 
      break 

Answer 2

您可以使用一个Counter做到这一点。 https://docs.python.org/2/library/collections.html#counter-objects

c = Counter() 
for d in dates: 
    c[d.week] += 1 # note I don't know the syntax for week off the top of my head