2016-05-13 29 views
1

结合在一起我有一组不相交的动态编写的类的,我想编译(和修复编译错误)分别。然后我想将它们组合成同一个组件。由于它们已经被编译,我不想简单地将它们的语法树传递给程序集编译(为了避免编译两次)。 我试图将它们编译成netmodules,然后使用这些netmodules作为对程序集的引用,但生成的程序集没有所需的类型。编译类分别使用罗斯林和它们在装配

这里是我的测试代码(非常类似于罗斯林的CompilationEmitTests.MultipleNetmodulesWithPrivateImplementationDetails())

public static class Program 
{ 

    public static void Main() 
    { 
     var s1 = @"public class A {internal object o1 = new { hello = 1, world = 2 }; public static string M1() { return ""Hello, "";}}"; 
     var s2 = @"public class B : A{internal object o2 = new { hello = 1, world = 2 };public static string M2(){ return ""world!"";}}"; 
     var s3 = @"public class Program{public static void Main(){ System.Console.Write(A.M1()); System.Console.WriteLine(B.M2());}}"; 
     var comp1 = CreateCompilationWithMscorlib("a1", s1, compilerOptions: TestOptions.ReleaseModule); 
     var ref1 = comp1.EmitToImageReference(); 

     var comp2 = CreateCompilationWithMscorlib("a2", s2, compilerOptions: TestOptions.ReleaseModule, references: new[] { ref1 }); 
     var ref2 = comp2.EmitToImageReference(); 

     var comp3 = CreateCompilationWithMscorlib("a3", s3, compilerOptions: TestOptions.ReleaseExe.WithModuleName("C"), references: new[] { ref1, ref2 }); 

     var ref3 = comp3.EmitToImageReference(); 

     IEnumerable<byte> result = comp3.EmitToArray(); 

     Assembly assembly = Assembly.Load(result.ToArray()); 

     Module module = assembly.GetModule("C"); 

     Type prog = module.GetType("Program"); 

     object instance = Activator.CreateInstance(prog); 

     MethodInfo method = prog.GetMethod("Main"); 

     method.Invoke(null, null); 
    } 

    public static ImmutableArray<byte> ToImmutable(this MemoryStream stream) 
    { 
     return ImmutableArray.Create<byte>(stream.ToArray()); 
    } 

    internal static ImmutableArray<byte> EmitToArray 
    (
     this Compilation compilation, 
     EmitOptions options = null, 
     Stream pdbStream = null 
    ) 
    { 
     var stream = new MemoryStream(); 

     if (pdbStream == null && compilation.Options.OptimizationLevel == OptimizationLevel.Debug) 
     { 
      pdbStream = new MemoryStream(); 
     } 

     var emitResult = compilation.Emit(
      peStream: stream, 
      pdbStream: pdbStream, 
      xmlDocumentationStream: null, 
      win32Resources: null, 
      manifestResources: null, 
      options: options); 

     return stream.ToImmutable(); 
    } 
    public static MetadataReference EmitToImageReference(
     this Compilation comp 
    ) 
    { 
     var image = comp.EmitToArray(); 
     if (comp.Options.OutputKind == OutputKind.NetModule) 
     { 
      return ModuleMetadata.CreateFromImage(image).GetReference(display: comp.AssemblyName); 
     } 
     else 
     { 
      return AssemblyMetadata.CreateFromImage(image).GetReference(display: comp.AssemblyName); 
     } 
    } 

    private static CSharpCompilation CreateCompilationWithMscorlib(string assemblyName, string code, CSharpCompilationOptions compilerOptions = null, IEnumerable<MetadataReference> references = null) 
    { 
     SourceText sourceText = SourceText.From(code, Encoding.UTF8); 
     SyntaxTree syntaxTree = SyntaxFactory.ParseSyntaxTree(sourceText, null, ""); 

     MetadataReference mscoreLibReference = AssemblyMetadata.CreateFromFile(typeof(string).Assembly.Location).GetReference(); 

     IEnumerable<MetadataReference> allReferences = new MetadataReference[] { mscoreLibReference }; 

     if (references != null) 
     { 
      allReferences = allReferences.Concat(references); 
     } 

     CSharpCompilation compilation = CSharpCompilation.Create 
     (
      assemblyName, 
      new[] {syntaxTree}, 
      options : compilerOptions, 
      references: allReferences 
     ); 

     return compilation; 
    } 

} 

在main()抛出的静态方法调用(例外),因为它无法找到参考A和B类。

我在做什么错?

+0

放入堆栈跟踪可能会有帮助。 – muglio

+0

动态程序(由字符串s3定义)无法找到对A和B的引用(位于字符串s1和s2中定义的netmodules中)。没有什么特别的Roslyn。 –

+1

如果其他人有兴趣,解决方案是在这里:https://github.com/dotnet/roslyn/issues/11297。 – svick

回答

0

下面是用户0xd4d张贴在Github上对同一个问题的答案。我测试了一下它的工作原理:

必须调用的LoadModule的netmodules需要访问

assembly.LoadModule("a1.netmodule", a1_netmodule_bytes); 
assembly.LoadModule("a2.netmodule", a2_netmodule_bytes); 

如果你他们都保存到磁盘之前,你并不需要这样做。

我还是不明白他的意思时指出,如果我把它保存到硬盘上,我不会要做到这一点。