如何从Java SOAP服务获得响应？

Question

我需要创建一个应用程序来获得xml响应从这个服务http://www.mcds.co.il/YouTube/ChanelApi.asmx没有额外的库，但我不知道我该怎么做。请帮助我

Answer 1

URL url = new URL("http://www.mcds.co.il/YouTube/ChanelApi.asmx"); 


    //generate your xml 
    String data = "<?xml version=\"1.0\" encoding=\"utf-8\"?>\r\n" + 
      "<soap:Envelope xmlns:xsi=\"http://www.w3.org/2001/XMLSchema-instance\" xmlns:xsd=\"http://www.w3.org/2001/XMLSchema\" xmlns:soap=\"http://schemas.xmlsoap.org/soap/envelope/\">\r\n" + 
      " <soap:Body>\r\n" + 
      " <GetChanel xmlns=\"http://tempuri.org/\">\r\n" + 
      "  <CategoryName>string</CategoryName>\r\n" + 
      " </GetChanel>\r\n" + 
      " </soap:Body>\r\n" + 
      "</soap:Envelope>"; 


    HttpURLConnection conn = (HttpURLConnection) url.openConnection(); 
    conn.setRequestMethod("POST"); 
    conn.setRequestProperty("Content-Type", "text/xml"); 

    conn.setRequestProperty("Content-Length", Integer.toString(data.getBytes().length)); 
    conn.setRequestProperty("SOAPAction","\"http://tempuri.org/GetChanel\""); 

    conn.setUseCaches (false); 
    conn.setDoOutput(true); 
    conn.setDoInput(true); 

    DataOutputStream wr = new DataOutputStream (
      conn.getOutputStream()); 
    wr.writeBytes(data); 
    wr.flush(); 
    wr.close(); 

    final char[] buffer = new char[0x10000]; 
    StringBuilder out = new StringBuilder(); 
    Reader in = new InputStreamReader(conn.getInputStream(), "UTF-8"); 
    int read; 
    do { 
     read = in.read(buffer, 0, buffer.length); 
     if (read>0) { 
     out.append(buffer, 0, read); 
     } 
    } while (read>=0); 
    System.out.println(out); 

    //parse out 

Answer 2

您可以使用apache的Axis生成SOAP客户端代码，请参阅“使用Web服务”部分。明确了解发生了什么的最好方法是使用Axis附带的WSDL2Java工具来生成客户端存根。这将为您构建一个SOAP客户端，您可以查看模型对象并开始针对它们开发。

WSDL2Java将WSDL URL作为输入，并为该WSDL生成一个Java客户端。