如何从数组更新表格？

Question

$query = "SELECT users FROM tabl ORDER BY RAND()"; 
$result = mysql_query ($query) 
    or die ("Query '$query' failed with error message: \"" . mysql_error() . '"'); 

while ($row = mysql_fetch_array($result)) { 
    $users[] = $row[0]; 
} 

$current = end($users); 
$partners = array(); 
foreach ($users as $user) 
{ 
     $partners[$user] = $current; 
     $current = $user; 
} 
print_r($partners); 

$query2 = "UPDATE tabl SET partner = {$partners[0]} WHERE users = '$users'"; 
mysql_query ($query2) 
    or die ("<br>Query '$query2' failed with error message: \"" . mysql_error() . '"'); 

这就是我正在使用的代码。在query2之前一切都很好。我试过了我能想到的所有变化，但没有任何效果。

表上有两个字段：用户和合作伙伴。代码以随机顺序拉取用户，然后将它们分配给彼此成圈。我需要使用作业来填充合作伙伴字段。

Answer 1

广场foreach循环内更新查询，那么你的合作伙伴和用户变量，而跳水手入阵以后：

foreach ($users as $user) 
{ 
     $partners[$user] = $current; 
     $current = $user; 
     $query2 = "UPDATE tabl SET partner = '{$partners[$user]}' WHERE users = '{$user}'"; 
     mysql_query ($query2) 
      or die ("<br>Query '$query2' failed with error message: \"" . mysql_error() 
} 

Answer 2

使用WHERE users IN ('.implode(',',$users).')'

Answer 3

我的代码更改：

$current = end($users); 
$partners = array(); 
foreach ($users as $user) 
{ 
    $partners[$user] = $current; 
    $current = $user; 
    $query2 = "UPDATE tabl SET partner = {$partners[$user]} WHERE users = '$user'"; 
    mysql_query ($query2) 
     or die ("<br>Query '$query2' failed with error message: \"" . mysql_error() . '"'); 
} 
print_r($partners); 

但你也可以做取决于你想要的结果如下：

$userList = join(',', $users); 
$query2 = "UPDATE tabl SET partner = {$partners[0]} WHERE users IN ($userList)"; 
mysql_query ($query2) 
    or die ("<br>Query '$query2' failed with error message: \"" . mysql_error() . '"');