使用标题时，从一个脚本刷新数据，而不是从另一个脚本？

Question

我使用两个脚本，一个用于从SQL中删除，另一个用于添加到数据库。

我遇到的问题是，在运行添加脚本时，它将刷新即时显示更改的页面。然而，在运行删除脚本时，它不会立即刷新它，似乎它会缓存输出？

如果它确实缓存了它重定向到的输出，为什么一个脚本显示添加而另一个不显示删除？

添加脚本

// Set a URL for the user to be redirected to 
$header_URL = "Location: ".WEBURL.DOCROOT."pages/parents-evening/{$_SESSION['status']}/"; 


// SQL statement using the variables from the user to insert into a specific table 
$sql = "INSERT INTO $table ($columns) VALUES ($values);"; 

// Check that the query was successful 
if(mysqli_query($conn, $sql)) 
{ 
    // Success 
    // Closes the database connection 
    mysqli_close($conn); 
    // Sets the redirect location 
    header($header_URL); 
    // Exits the script 
    exit(); 
} 
else 
{ 
    // Fail 
    // Closes the database connection 
    mysqli_close($conn); 
    // Sets the redirect location 
    header($header_URL); 
    // Exits the script 
    exit(); 
} 

删除脚本

// Set a URL for the user to be redirected to 
$header_URL = "Location: ".WEBURL.DOCROOT."pages/parents-evening/{$_SESSION['status']}/"; 

// SQL statement to delete from the table provided where the ID is equal to either the POST or GET value 
$sql = "DELETE FROM {$table} WHERE id = {$_POST['delete_id']}{$_GET['delete_id']}"; 

// Check the query was successful 
if(mysqli_query($conn, $sql)) 
{ 
    // Success 
    // Closes the database connection 
    mysqli_close($conn); 
    // Sets the redirect location 
    header($header_URL); 
    // Exits the script 
    exit(); 
} 
else 
{ 
    // Fail 
    // Closes the database connection 
    mysqli_close($conn); 
    // Sets the redirect location 
    header($header_URL); 
    // Exits the script 
    exit(); 
} 

Answer 1

似乎问题是，在此声明：

$ SQL =“DELETE FROM {$表} WHERE ID = {$ _POST [ 'delete_id']} {$ _ GET [ 'delete_id']}“;

如果从POST越来越delete_id查询将是：

$sql = "DELETE FROM {$table} WHERE id = ".$_POST['delete_id']; 

如果从GET越来越delete_id查询将是：

$sql = "DELETE FROM {$table} WHERE id = ".$_GET['delete_id']; 

如果只有一个记录是删除（因为似乎id是主键，所以只会有一条记录），我会推荐使用limit 1，因为它会加快删除过程，如果你有巨大的da ta在你的桌子上。

限制1将告诉数据库只删除一条记录，因此当1条记录被删除时它将停止执行。

你最终的查询将是：

对于POST

$sql = "DELETE FROM {$table} WHERE id = ".$_POST['delete_id']." LIMIT 1"; 

对于GET

$sql = "DELETE FROM {$table} WHERE id = ".$_GET['delete_id']." LIMIT 1";