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我在我的PHP脚本运行该SQL:如何正确地从一个SQL表PHP脚本隔离元素
$sql = "SELECT u.id AS id, ul.meta_value AS lastpaymentdate, rd.meta_value AS noemails
FROM wp_users u
LEFT JOIN wp_usermeta rd ON rd.user_id=u.id AND rd.meta_key='noemails'
LEFT JOIN wp_usermeta ul ON ul.user_id=u.id AND ul.meta_key='lastpaymentdate'
WHERE u.user_email = '[email protected]'";
$rs = $db->Execute($sql);
下面是数据,它会输出,如果我跑了它在SQL控制台:
+------+-----------------+----------+
| id | lastpaymentdate | noemails |
+------+-----------------+----------+
2523 2013-10-30 0
我需要将lastpaymentdate(2013-10-30)获取到数组$ lastRenewalDateParts中。
我想出是:
$lastRenewalDateParts = explode('-', $rs->data[0][1]);
然而,它不能正常工作。它给了我一个空阵列。我哪里可能会出错?
编辑:这里是的print_r($ RS)的结果:
mysqli_driver_ResultSet Object
(
[connectionId] => mysqli Object
(
[affected_rows] => 1
[client_info] => 5.5.30
[client_version] => 50530
[connect_errno] => 0
[connect_error] =>
[errno] => 0
[error] =>
[field_count] => 3
[host_info] => Localhost via UNIX socket
[info] =>
[insert_id] => 0
[server_info] => 5.5.38-35.2
[server_version] => 50538
[stat] => Uptime: 2030485 Threads: 19 Questions: 2452324326 Slow queries: 6246 Opens: 22784920 Flush tables: 1 Open tables: 16800 Queries per second avg: 1207.752
[sqlstate] => 00000
[protocol_version] => 10
[thread_id] => 44573449
[warning_count] => 0
)
[fields] => Array
(
[id] => 2523
[lastpaymentdate] => 2013-10-30
[noemails] => 0
)
[resultId] => mysqli_result Object
(
[current_field] => 0
[field_count] => 3
[lengths] => Array
(
[0] => 4
[1] => 10
[2] => 1
)
[num_rows] => 1
[type] => 0
)
[_currentRow] => 0
[_numOfRows] => 1
[_numOfFields] => 3
[fetchMode] => 1
[EOF] =>
[record] => Array
(
)
)
'$ rs-> data [0] [1]'是否包含日期? – 2014-10-17 16:51:11
它应该是,但它是空的。 – msargenttrue 2014-10-17 16:53:21
如果你使用'print_r($ rs)',你会得到什么? – 2014-10-17 16:59:23