2016-11-22 46 views

回答

0

请尝试以下方法。它列出了所有问题已经回答的所有PSPID。

SELECT DISTINCT qq.PSPID 
    FROM PSP_QUESTION_MASTER AS qq 
WHERE NOT EXISTS (SELECT q.QUESTIONID FROM PSP_QUESTION_MASTER AS q 
        WHERE q.PSPID = qq.PSPID 
        EXCEPT 
        SELECT a.QUESTIONID FROM PSP_ANSWER_MASTER AS a 
        WHERE a.PSPID = qq.PSPID); 
+0

这对我有效......非常感谢:) – SUPERGIRL

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