搜索哈希的数组，看是否在一个给定的哈希特定元素在Ruby中

Question

另一个阵列内匹配任何字符串考虑下面的代码：

cons = [ 
    { "FirstName" => "Bill", 
    "LastName" => "Wingy", 
    "Phone1" => "(800) 552-3209", 
    "Phone2" => "828 283-1134" 
    }, 
    { "FirstName" => "Ted", 
    "LastName" => "Dimble", 
    "Phone1" => "(823) 813-2834", 
    "Phone2" => "8823 232-2342" 
    } 
] 

pait_nums = [ "8282831134", "8282831132344" ] 

你如何搜索cons阵列返回哈希情形之一"Phone1".gsub(/\D/, '')或"Phone2".gsub(/\D/, '')匹配pait_nums数组中的任何字符串？

Answer 1

让我们试试这个：

cons.select{ |con| pait_nums.include?(con['Phone1'].gsub(/\D/, '')) || pait_nums.include?(con['Phone2'].gsub(/\D/, '')) } 

或使其短

phone_keys = %w(Phone1 Phone2) 
cons.select{ |con| con.slice(*phone_keys).values.any?{ |val| pait_nums.include?(val.gsub(/\D/, '')) } } 

Answer 2

如果你正在使用的轨道，那么你可以使用红宝石present可以使用any?

cons.select{ |con| ([con['Phone1'].gsub(/\D/, ''), con['Phone2'].gsub(/\D/, '')] & pait_nums).present?} 

在红宝石你可以使用any?作为

cons.select{ |con| ([con['Phone1'].gsub(/\D/, ''), con['Phone2'].gsub(/\D/, '')] & pait_nums).any?} 

Answer 3

cons.select do |c| 
    c.select do |k, _| 
    k =~ /\APhone\d\z/      # select Phone* keys 
    end.values        # get values 
    .any? do |p| 
     pait_nums.include? p.gsub(/\D/, '') # get only matches 
    end 
end 

，或者对于键的任意集合来检查：

keys = %w|Phone1 Phone2| 
cons.select do |c| 
    c.select do |k, _| 
    keys.include? k      # select Phone* keys 
    end.values.any? do |p| 
    pait_nums.include? p.gsub(/\D/, '') # get only matches 
    end 
end 

Answer 4

phones = ["Phone1", "Phone2"] 
cons.find { |h| (h.values_at(*phones).map { |s| s.gsub(/\D/,"") } & pait_nums).any? } 
    #=> {"FirstName"=>"Bill", 
    # "LastName"=>"Wingy", 
    # "Phone1"=>"(800) 552-3209", 
    # "Phone2"=>"828 283-1134"} 

的步骤：

find最初通过的cons第一值到所述块并且设置块变量h至该值：

h = { "FirstName" => "Bill", 
     "LastName" => "Wingy", 
     "Phone1" => "(800) 552-3209", 
     "Phone2" => "828 283-1134" } 

以下块计算然后执行：

a = h.values_at(*phones) 
    #=> ["(800) 552-3209", "828 283-1134"] 
b = a.map { |s| s.gsub(/\D/,"") } 
    #=> ["8005523209", "8282831134"] 
c = b & pait_nums 
    #=> ["8005523209", "8282831134"] & ["8282831134", "8282831132344"] 
    #=> ["8282831134"] 
c.any? 
    #=> true 

c由于是true，find返回h。如果是cfalse，则第二个哈希将被发送到该块。