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我想完成Udacity课程并行编程的作业#2。我遇到了一个我无法解决的CUDA错误。当我启动一个内核时,该错误会被嵌入,该内核旨在将格式为“RGBRGBRGB”的图像分隔为三个单独的“RRR”“GGG”和“BBB”阵列。看到错误“未指定的启动失败”并没有给我任何具体的继续我不知道如何解决我的问题。Udacity并行编程,未指定启动失败cudaGetLastError()
这是调用来启动整个过程的“主”功能。遇到错误后,我将剩下的工作留给了其他人,以便稍后查找。
void your_gaussian_blur(const uchar4 * const h_inputImageRGBA, uchar4 * const d_inputImageRGBA, uchar4* const d_outputImageRGBA, const size_t numRows, const size_t numCols,
unsigned char *d_redBlurred,
unsigned char *d_greenBlurred,
unsigned char *d_blueBlurred,
const int filterWidth)
{
// Maximum number of threads per block = 512; do this
// to keep this compatable with CUDa 5 and lower
// MAX > threadsX * threadsY * threadsZ
int MAXTHREADSx = 16;
int MAXTHREADSy = 16; // 16 x 16 x 1 = 512
// We want to fill the blocks so we don't waste this blocks threads
// I wonder if blocks can intermix in a physical core?
// Either way this method makes things "clean"; one thread per px
int nBlockX = numCols/MAXTHREADSx + 1;
int nBlockY = numRows/MAXTHREADSy + 1;
const dim3 blockSize(MAXTHREADSx, MAXTHREADSy, 1);
const dim3 gridSize(nBlockX, nBlockY, 1);
separateChannels<<<gridSize, blockSize>>>(
h_inputImageRGBA,
numRows,
numCols,
d_red,
d_green,
d_blue);
// Call cudaDeviceSynchronize(), then call checkCudaErrors() immediately after
// launching your kernel to make sure that you didn't make any mistakes.
cudaDeviceSynchronize(); checkCudaErrors(cudaGetLastError());
这里是功能separateChannels
//This kernel takes in an image represented as a uchar4 and splits
//it into three images consisting of only one color channel each
__global__
void separateChannels(const uchar4* const inputImageRGBA,
int numRows,
int numCols,
unsigned char* const redChannel,
unsigned char* const greenChannel,
unsigned char* const blueChannel)
{
//const int2 thread_2D_pos = make_int2(blockIdx.x * blockDim.x + threadIdx.x, blockIdx.y * blockDim.y + threadIdx.y);
const int col = blockIdx.x * blockDim.x + threadIdx.x;
const int row = blockIdx.y * blockDim.y + threadIdx.y;
//if (thread_2D_pos.x >= numCols || thread_2D_pos.y >= numRows)
// return;
if (col >= numCols || row >= numRows)
return;
//const int thread_1D_pos = thread_2D_pos.y * numCols + thread_2D_pos.x;
int arrayPos = row * numCols + col;
uchar4 rgba = inputImageRGBA[arrayPos];
redChannel[arrayPos] = rgba.x;
greenChannel[arrayPos] = rgba.y;
blueChannel[arrayPos] = rgba.z;
}
我想我把必要的话,请让我知道如果没有。
是的,这证明是问题。我只是来这里说的。谢谢! – KDecker 2014-09-21 21:13:59