改变每个循环成环

我在VBA改变每个循环成环

Dim userBeanList As MSXML2.IXMLDOMNodeList 
Dim userbean As MSXML2.IXMLDOMNode 
Dim beanChild As MSXML2.IXMLDOMNode 

XMLDOC.Load ("https://www.catch.api") 

r = 4 
Set userBeanList = XMLDOC.SelectNodes("/response/responseBody/responseList/item[recordType='TPI']") 
For Each userbean In userBeanList 
    For Each beanChild In userbean.ChildNodes 
    If beanChild.nodeName = "catch" Then GoTo NextIteration 

     Sheets("Sheet2").Cells(r, 1) = beanChild.nodeName 
     Sheets("Sheet2").Cells(r, 2) = beanChild.Text 

    r = r + 1 
NextIteration: 
    Next beanChild 
Next userbean

下面的代码目前，我公司通过所有的节点，然后在这种情况下，忽略了节点称为“捕获”循环再进入下一个迭代，因为我不需要该节点或节点值。而不是这样做我怎么会改变我的循环到一个我可以直接去感兴趣的节点，因此不必跳过似乎效率低下的迭代？

/////之后，从冻糕

Dim userBeanList As MSXML2.IXMLDOMNodeList 
Dim userbean As MSXML2.IXMLDOMNode 
Dim beanChild As MSXML2.IXMLDOMNode 

XMLDOC.Load ("http://www.catch.api") 

r = 4 

Set userBeanList = XMLDOC.SelectNodes("/response/responseBody/responseList/item[recordType='TPI']/*[not(local-name)='catch']") 
For Each userbean In userBeanList 

     Sheets("Sheet2").Cells(r, 1) = userbean.nodeName 

     Sheets("Sheet2").Cells(r, 2) = userbean.Text 

     r = r + 1 

Next userbean

来源

2016-03-03 Ingram

http://stackoverflow.com/questions/24188773/xpath-to-select-all-and-exclude-child-and-its-children –

它可能会更高效地说它beanChild.nodeName <>“catch”然后做东西 – justkrys

帮助考虑XPath表达式排除。以下指定任何name()或local-name()不等于'catch'的孩子。这甚至可以避免子节点上的内部For Each循环。

Set userBeanList = XMLDOC.SelectNodes("/response/responseBody/responseList" _ 
            & "/item[recordType='TPI']/*[not(local-name)='catch']")

或者，具有self

Set userBeanList = XMLDOC.SelectNodes("/response/responseBody/responseList" _ 
            & "/item[recordType='TPI']/*[not(self::catch)]")

来源

2016-03-04 22:49:18 Parfait

这看起来非常有趣，如果我有一个或，例如'catch'或'reprive'，我将如何更改集合 – Ingram

只需添加'或'条件：'[not（self :: catch或self :: reprive）]' – Parfait

改变每个循环成环

回答

相关问题