mysql + JOIN查询的问题

Question

好的伙计们，很抱歉，因为我看到了一些mysql JOIN示例，但我似乎无法让它工作。

“销售”

---------------------- 
idcustomer | datecode 
---------------------- 
1   | 20120503 
1   | 20120503 
1   | 20120503 
2   | 20120503 
3   | 20120503 

我想知道谁是最大买家....在多少次客户从我这里买走的东西在especific天方面（是的，我用一些奇怪的格式日期我知道，请不要介意说）......，所以我做的：

SELECT idcustomer, COUNT(idcustomer) FROM sales WHERE datecode = 20120503 GROUP BY idcustomer ORDER BY COUNT(idcustomer) DESC 

，我也得到：

----------------------------- 
idcustomer | Count(idcustomer) 
----------------------------- 
1   | 3 
2   | 1 
3   | 1 

的问题是... SI NCE我也有表：

“客户”

---------------------- 
| name | id_customer | 
---------------------- 
Jess | 1 
Matt | 2 
Perry | 3 

及以下就是我想达到什么样的....怎么办呢？

--------------------------------------------- 
customer.name | idcustomer | Count(idcustomer) 
--------------------------------------------- 
Jess   | 1   | 3 
Matt   | 2   | 1 
Perry  | 3   | 1 

Answer 1

SELECT customer.name, idcustomer, COUNT(idcustomer) 
FROM sales 
JOIN customer 
ON sales.idcustomer = customer.id_customer 
WHERE datecode = 20120503 
GROUP BY idcustomer 
ORDER BY COUNT(idcustomer) DESC 

看到它联机工作：sqlfiddle

Answer 2

你需要做这种方式 -

SELECT idcustomer, c.name, COUNT(idcustomer) 
FROM sales s inner join customer c on (s.idcoustomer=c.id_customer) 
WHERE datecode = 20120503 
GROUP BY idcustomer, c.name 
ORDER BY COUNT(idcustomer) DESC 

Answer 3

希望这将有助于::

Select cust_ref.idcustomer, cust_ref.COUNT(idcustomer), customer.name 
from 
(SELECT idcustomer, COUNT(idcustomer) FROM sales WHERE datecode = 20120503 
GROUP BY idcustomer) cust_ref 
inner join customer on (sales.idcustomer = customer.id_customer) 
ORDER BY COUNT(idcustomer) DESC 

Answer 4

SELECT 
    t1.name,t2.count_buy,t2.idcustomer 
    FROM customer as t1, 
(SELECT 
    idcustomer,COUNT(idcustomer) as count_buy 
     FROM `sales` 
     WHERE datecode = 20120503 
     GROUP BY idcustomer 
     ORDER BY COUNT(idcustomer) DESC) t2 
    WHERE 
    t1.idcustomer =t2.idcustomer