SQL最后工作

Question

天

我有以下查询

select Case.casekey, LoginName, startdatedate, SenttoClientDate 
from case with (nolock) 
where SenttoClientDate = dateadd(day,-1, cast(getdate() as date)) 

这将返回结果，其中{} senttoclientdate昨日=。

问题是，如果我在星期一运行这个功能，我会得到星期天的结果，但我想要上一工作日。所以如果我在星期一跑步，我想要周五的成绩。

Answer 1

的情况下扔在日期部分

where SentToClientDate = 
    case when datepart(dw,getdate()) = 2 then dateadd(day,-3,getdate()) -- Monday is day 2, for no reason whatsoever 
     else dateadd(day,-1,getdate()) 
    end 

Answer 2

你可以这样说：

WHERE SenttoClientDate = (SELECT DATEADD(DAY, CASE DATENAME(WEEKDAY, GETDATE()) 
        WHEN 'Sunday' THEN -2 
        WHEN 'Monday' THEN -3 
        ELSE -1 END, DATEDIFF(DAY, 0, GETDATE()))) 

Answer 3

在病症使用的外壳下面，

select Case.casekey, LoginName, startdatedate, SenttoClientDate 
    from case with (nolock) 
    where SentToClientDate = 
    case when datepart(dw,getdate()) = 2 then dateadd(day,-3,getdate()) 
     when datepart(dw,getdate()) = 1 then dateadd(day,-2,getdate()) 
     else dateadd(day,-1,getdate()) 
    end 

Answer 4

能不能请你有了这个，这是非常简单和完美的解决方案：

SELECT Case.casekey, LoginName, startdatedate, SenttoClientDate 
FROM case with (nolock) 
WHERE SenttoClientDate = 
CAST(DATEADD(dd, 
    CASE WHEN DATEPART(weekday, GETDATE()) = 6 THEN 0 
    ELSE (6-(DATEPART(weekday, GETDATE())+7)) END, GETDATE()) AS DATE)