添加毫秒到timeval C++

Question

使用下面的代码我可以得到当前时间以毫秒为单位。现在我想将毫秒添加到系统时间。任何提示？

#include <stdio.h> 
#include <sys/time.h> 

int main (int argc, char** argv) { 
    struct timeval time; 
    gettimeofday (&time, NULL); 

    long systemtime = time.tv_sec*1000L + time.tv_usec/1000L; 

    printf("Time in milliseconds: %ld milliseconds\n", systemtime); 
    //sample output: 1492592522106 

    return 0; 
} 

编辑：解决

#include <stdio.h> 
#include <sys/time.h> 

int main (int argc, char** argv) { 
    struct timeval time; 
    gettimeofday (&time, NULL); 

    printf("Time in milliseconds: %ld milliseconds\n", time.tv_sec*1000L + 
    (time.tv_usec/1000L)); 
    printf("Time in milliseconds+300: %ld milliseconds\n", time.tv_sec*1000L 
    + (time.tv_usec/1000L+300)); 
    printf("usec: %ld", time.tv_usec/1000L); 

    return 0; 
} 

输出：

Time in milliseconds: 1492595580965 milliseconds (Wed, 19 Apr 2017 09:53:00.965 GMT) 
Time in milliseconds+300: 1492595581265 milliseconds (Wed, 19 Apr 2017 09:53:01.265 GMT) 
usec: 965 

Answer 1

你的adjtime尝试（）？ 。 http://man7.org/linux/man-pages/man3/adjtime.3.html

Answer 2

您可以使用std::chrono库来执行此任务。 下面的代码片段将帮助您完成此，

auto now = std::chrono::system_clock::now().time_since_epoch(); 
auto t100ms = std::chrono::milliseconds(100); 
auto time = now + t100ms; 
std::cout << std::chrono::duration_cast<std::chrono::milliseconds>(time).count();