删除<a></a>之间的文本但不是href或<span></span>使用PHP

Question

尝试从</span>和</a>之间删除文本。我想只是在</span>之后删除some text here，以便它只显示图标。

$bad_string = '<li class="someclasses"><a target="_blank" href="http:www.example.com/dir/handle"><span></span>some text here</a></li>'; 

$good_string = '<li class="someclasses"><a target="_blank" href="http:www.example.com/dir/handle"><span></span></a></li>'; 

目前呼应什么：

<ul id="menu-social-menu-1" class="menu"> 
    <li class="someclasses"><a target="_blank" href="http:www.example.com/dir/handle"><span></span>some text here</a></li> 
    <li class="someclasses"><a target="_blank" href="http:www.example.com/dir/handle"><span></span>some text here</a></li> 
    <li class="someclasses"><a target="_blank" href="http:www.example.com/dir/handle"><span></span>some text here</a></li> 
    <li class="someclasses"><a target="_blank" href="http:www.example.com/dir/handle"><span></span>some text here</a></li> 
    <li class="someclasses"><a target="_blank" href="http:www.example.com/dir/handle"><span></span>some text here</a></li> 
</ul> 

要重复一下：

<ul id="menu-social-menu-1" class="menu"> 
    <li class="someclasses"><a target="_blank" href="http:www.example.com/dir/handle"><span></span></a></li> 
    <li class="someclasses"><a target="_blank" href="http:www.example.com/dir/handle"><span></span></a></li> 
    <li class="someclasses"><a target="_blank" href="http:www.example.com/dir/handle"><span></span></a></li> 
    <li class="someclasses"><a target="_blank" href="http:www.example.com/dir/handle"><span></span></a></li> 
    <li class="someclasses"><a target="_blank" href="http:www.example.com/dir/handle"><span></span></a></li> 
</ul> 

WordPress中使用这个下面的代码之后的文字跨度仍然存在。它不会去掉</span>之后的文字。我的错误是什么？在这里：

<?php if (has_nav_menu('social-menu')) { 
    $menu = wp_nav_menu(array('theme_location' => 'social-menu', 'fallback_cb' => '', 'echo' => false)); 

    function convertURL($menu) { 
     return preg_replace("/<a target=\"_blank\" href=\"([^\"]+?)\"><span><\/span>.*?<\/a>/", "<a target=\"_blank\" href=\"$1\"><span></span></a>", $menu); 
    } 

    echo $menu; 
    } 
?> 

Answer 1

你为什么不只是解决一个正则表达式中删除的东西？

function convertURL($url) { 
    return preg_replace("/<a href=\"([^\"]+?)\">.*/", "<a href=\"$1\"><span></span></a>", $url); 
} 
// input: <a href="http:www.example.com/dir/handle"><span></span>some text here</a> 
// output: <a href="http:www.example.com/dir/handle"><span></span></a> 

编辑：
test.php的：

<?php 
function convertURL($url) { 
    return preg_replace("/<a href=\"([^\"]+?)\">.*/", "<a href=\"$1\"><span></span></a>", $url); 
} 

foreach(['<a href="http://linkedin.com/some/vanity"><span></span>some text here</a>', '<a href="http:www.example.com/dir/handle"><span></span>some text here</a>'] as $url) { 
    echo "$url => "; 
    echo convertURL($url)."\n"; 
} 

PHP test.php的：

$ php /tmp/test.php 
<a href="http://linkedin.com/some/vanity"><span></span>some text here</a> => <a href="http://linkedin.com/some/vanity"><span></span></a> 
<a href="http:www.example.com/dir/handle"><span></span>some text here</a> => <a href="http:www.example.com/dir/handle"><span></span></a> 

Answer 2

强制性https://stackoverflow.com/a/1732454/2191572但这应该工作。

如果我可以重新字你的要求，然后要在</span>和</a>之间

$bad_string = '<a href="http:www.example.com/dir/handle"><span>social icon</span>some text here</a>'; 

$parts = explode('</span>', $bad_string); // explode on </span> and save the array 
array_pop($parts); // remove last element of array which should be "some text here</a>" 
$parts[] = '</a>'; // re-add the </a> 

$good_string = implode('</span>', $parts); // re-join the array on </span> 

echo $good_string;