SQL Server - LIKE [XXXX]

Question

我想只返回包含特定字段中的文本[XXXX]的值。 我的查询返回有4位数字的值，因为我假设SQL服务器将[XXXX]视为任何具有4位数字的数字。

我有一个测试查询下面的值列表来演示这个问题。

select X.VadDesc 
From (VALUES 
('Product AAAA Description'), 
('Product BBBB Description'), 
('Product [XXXX] Description'), 
('Product2 [XXXX] Description'), 
('Product 2 [AAAA] Description'), 
('Product X 1234 Description'), 
('Product X 1235 Description'), 
('Product X 1236 Description'), 
('Product X 1237 Description') 
) as X (VadDesc) 
Where X.VadDesc like '%[XXXX]%' 

我的查询应该只返回：

Product [XXXX] Description 
Product2 [XXXX] Description 

但它返回：

Product [XXXX] Description 
Product2 [XXXX] Description 
Product X 1234 Description 
Product X 1235 Description 
Product X 1236 Description 
Product X 1237 Description 

我怎样才能做到这一点？ 我不只是想寻找XXXX，因为这可能是我不想返回的行。

Answer 1

select X.VadDesc 
From (VALUES 
('Product AAAA Description'), 
('Product BBBB Description'), 
('Product [XXXX] Description'), 
('Product2 [XXXX] Description'), 
('Product 2 [AAAA] Description'), 
('Product X 1234 Description'), 
('Product X 1235 Description'), 
('Product X 1236 Description'), 
('Product X 1237 Description') 
) as X (VadDesc) 
Where X.VadDesc like '%[[]XXXX]%' 

Answer 2

使用Escape character转义[像这样'%\[XXXX\]%' {escape '\'}。

查询

select X.VadDesc 
From (VALUES 
('Product AAAA Description'), 
('Product BBBB Description'), 
('Product [XXXX] Description'), 
('Product2 [XXXX] Description'), 
('Product 2 [AAAA] Description'), 
('Product X 1234 Description'), 
('Product X 1235 Description'), 
('Product X 1236 Description'), 
('Product X 1237 Description') 
) as X (VadDesc) 
Where X.VadDesc like '%\[XXXX\]%' {escape '\'} 

SQL Fiddle