选择从不同的标准SQL

Question

TABLE玩家表中的值

 
idPlayer | name | 

    1 | name1 | 
    2 | name2 | 
    3 | name3 | 
    4 | name4 | 

表匹配

 
idMatch | idPlayer1 | idPlayer2 | date | 

    1  |  1  |  2  | 03-03 | 
    2  |  3  |  4  | 03-03 | 
    3  |  1  |  4  | 03-03 | 

Expeted

 
idMatch | player1 | player2 | date | 

    1  | name1 | name2 | 03-03 | 
    2  | name3 | name4 | 03-03 | 
    3  | name1 | name4 | 03-03 | 

我已经尝试了许多代码，仍然没有找到一个解决方案。

Answer 1

我做了这个

SELECT idMatch, 
(SELECT name FROM t1 WHERE t2.idPlayer1=t1.idPlayer) as name1, 
(SELECT name FROM t1 WHERE t2.idPalyer2=t1.idplayer) as name2, 
date 
FROM calendario 

和它的作品。

Thaks

Answer 2

试试这个：

Select t1.idMatch AS idMatch, p1.name AS player1, p2.name AS player2, t1.date AS date 
FROM matches t1 
INNER JOIN player p1 ON t1.idPlayer1 = p1.idPlayer 
INNER JOIN player p2 ON t1.idPlayer2 = p2.idPlayer 

这应该为你正确地解码的球员。