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我可以使用iPhone中的任何网络API(如AFNetworking,MKNetworkKit等)将任何函数的服务器响应返回到其调用函数。在iPhone中返回HTTPS响应的网络API
目前我正在使用NSURLRequest的httpGet函数。我做了以下功能,但我无法将服务器响应返回给它的调用函数。请帮帮我。
func connserv(jsonString:NSDictionary) -> NSDictionary{
var abc: NSDictionary?
// This is the action performed when clicked on the Connect button on the connectivity screen
println("------------------Function connserv")
let prefs = NSUserDefaults.standardUserDefaults()
var IP: AnyObject = prefs.objectForKey("IP")!
var port: AnyObject = prefs.objectForKey("Port")!
println("IP in Connection : \(IP)")
println("port in Connection : \(port)")
prefs.synchronize()
//var learn = LearnNSURLSession()
let localizedModel = UIDevice.currentDevice().localizedModel
let model = UIDevice.currentDevice().model
let devicesystemVersion = UIDevice.currentDevice().systemVersion
println("HTTP request jsonString : \(jsonString)")
var request = NSMutableURLRequest(URL: NSURL(string: "https://\(IP):\(port)/")!)
var response: NSURLResponse?
var error: NSError?
//println("HTTP request jsonString : \(jsonString)")
var err: NSError?
request.HTTPBody = NSJSONSerialization.dataWithJSONObject(jsonString, options: nil, error: &err)
request.HTTPMethod = "POST"
request.setValue("application/json", forHTTPHeaderField: "Content-Type")
request.setValue("application/json", forHTTPHeaderField: "Accept")
// send the request
var learn = LearnNSURLSession()
println("HTTP request : \(request)")
learn.httpGet(request) {
(resultString, error) -> Void in
if error != nil
{
println("completion block")
}
else
{
let data = (resultString as NSString).dataUsingEncoding(NSUTF8StringEncoding)
var er: NSError?
let JSONdata: AnyObject = NSJSONSerialization.JSONObjectWithData(data!, options: .MutableContainers,error: &er)!
let abc: AnyObject = NSJSONSerialization.JSONObjectWithData(data!, options: .MutableLeaves, error:&er)!
println("abc : \(abc)")
println("JSONdata : \(JSONdata)")
learn.callback(result: resultString, error: error)
}
}
//return abc!;
}
Emrys57,我从服务器得到响应和一切。它没有问题。我想将服务器响应返回给connserv函数的调用函数。问题在那里。我希望你现在有个更好的主意 – 2015-04-02 14:31:37
尝试新版本 – emrys57 2015-04-02 14:50:32
我会尝试。我能否在异步连接中做同样的事情? – 2015-04-02 14:58:26