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我试图将以下sql命令上传到php myadmin。但是,我有一些有趣的错误。我试图解决它,但即使我仔细考虑,我也找不到错误发生的原因。php myadmin sql 1064触发器错误
错误:
MySQL said: Documentation
#1064 - You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'ON car_model
FOR INSERT
AS
declare @car_name VARCHAR(255)' at line 2
SQL:
CREATE TRIGGER TRG_Update
ON car_model
FOR INSERT
AS
DECLARE @car_name VARCHAR(255);
DECLARE @manufacturer_year VARCHAR(255);
DECLARE @car_type VARCHAR(255);
SELECT @car_name = i.car_name FROM inserted i;
SELECT @manufacturer_year = i.manufacturer_year FROM inserted i;
SELECT @car_type = i.car_type FROM inserted i;
INSERT INTO features
(car_name, manufacturer_year, car_type)
VALUES (@car_name, @manufacturer_year, @car_type);
GO
你能完全写完整的代码校正?我已经做了你写的东西,但仍然是同样的错误。 – demilg 2013-03-24 11:10:06
这就是整个代码,你不需要声明任何变量。什么是完整的错误信息生成? – 2013-03-24 11:11:23
它说你没有权限做这份工作。这是什么,我怎样才能解决它在PHP myadmin? – demilg 2013-03-24 11:26:07