类型数组中的布尔方法

Question

我无法编译此方法。此方法用于搜索类型为Event的数组。所以说，如果月份包含[1,2,3,4,5,6,7 * 8,9 *]，它将搜索有星号的那些并返回true

public static boolean isSignificant(Event[] month, String SearchValue) 
     { 
     boolean isFound = false; 
     for(int i = 0; i< month.length && isFound == false; i++) 
     { 

      if(month[i].contains(SearchValue)) // error on this line 
      { 
      isFound = true; 
      } 
     } 
     return isFound; 
     } 

Answer 1

有很多方法来搜索这种模式

1. if (value.endsWith("*")) {
2. if (value.matches(".*\\*$")) {
3. value.matches(".*?\\*$")

如

public class HelloWorld 
{ 
    static String[] month = new String[]{"1","2","3","4","5","6","7*","8","9*"}; 
    public static boolean isSignificant() 
     { 
      boolean isFound = false; 
      for(int i=0; i <month.length && isFound == false; i++) 
       { 
        if(month[i].endsWith("*")) 
         { 
          isFound = true; 
         } 
       } 
      return isFound; 
     } 

    public static void main(String []args) 
     { 
      HelloWorld obj = new HelloWorld(); 
      if(obj.isSignificant()) 
       { 
        System.out.println("The string ends with *"); 
       } 
      else 
       { 
        System.out.println("The string donot end with *"); 
       } 
     } 
} 

Answer 2

@ Jean-FrançoisSavard是对的，月份是类型事件，而你正在寻找一个字符串。如果你向我解释更多的信​​息，我可以帮助你更多，否则生病只是假设你的意思是一个字符串数组。

public class HelloWorld{ 

    public static void main(String []args){ 
     System.out.println("Hello World"); 
     String [] array = {"1","2","3","4*"} ; 
     if(isSignificant(array,"*")){ 
      System.out.println("Found"); 
     }else{ 
      System.out.println("Not found"); 
     } 
    } 

    public static boolean isSignificant(String[] month, String SearchValue) { 
     for(int i = 0; i< month.length; i++) { 

      if(month[i].contains(SearchValue)) { 
      return true; 
      } 
     } 
     return false; 
     } 
}