将整数转换为二进制返回错误的值

Question

我创建了一个数字转换器，我需要将整数转换为二进制。当我试图转换整数12。它给我一个值0 0 0 0 0 1 0 0而不是0 0 0 0 1 1 0 0。

代码：

number = int(input("Enter a integer between 255 and 0: ")) 
    if (number > 255) or (number < 0): 
     print("Please input less than 255!!!") 
    else: 
     a = False 

     for myCounter in range (8): 

      if (number % 2 == 1):#if remainder is equal to 1 
       myResult = ' 1 ' + myResult#add '1' character to the string 

      else: 
       (number % 2 == 0)#if input has no remainder 
       myResult = ' 0 ' + myResult#add '0' character to the string 

      number = number/2 

     print("Binary equivalent is: %s" %myResult) 

我如何四舍五入的0.5到1使用ROUND_HALF_UP？输出如下。

任何帮助将不胜感激谢谢！

Answer 1

该代码在Python 2.7中正常工作。对于Python 3.x尝试更换number = number/2到number=number//2

number = 12 
a = False 
myResult = '' 
for myCounter in range (8): 

    if (number % 2 == 1):#if remainder is equal to 1 
     myResult = ' 1 ' + myResult#add '1' character to the string 

    else: 
     (number % 2 == 0)#if input has no remainder 
     myResult = ' 0 ' + myResult#add '0' character to the string 

    number = number // 2 

print("Binary equivalent is: %s" %myResult)