用XML中的对象填充数组

Question

我有一个XML文件，我试图读取并转换为对象。我想要转换并将所有位置填充到位置对象，这些位置对象由电影ID，日期和金额定义。

这里是我的XML文件：

这里是我的代码扫描位置XML部分：

public void findLocations() throws ParseException { 

    NodeList nList = document.getElementsByTagName("location"); 
    Location[] locations = new Location[nList.getLength()]; 
    for (int temp = 0; temp < nList.getLength(); temp++) { 
     Node nNode = nList.item(temp); 

     if (nNode.getNodeType() == Node.ELEMENT_NODE) { 
      Element eElement = (Element) nNode; 
       locations[temp] = new Location(getTagValue("filmid", eElement), dateChanger(getTagValue("date", eElement)), getTagValue("amount", eElement)); 
     System.out.println(locations[temp].getAmount()); //Outputs the good values. 
     } 

    } 
System.out.println(locations[0].getAmount()); //Output : 5$ 
System.out.println(locations[1].getAmount()); //Output : 5$ 
System.out.println(locations[2].getAmount()); //Output : 5$ 
} 


private static String getTagValue(String sTag, Element eElement) { 

    NodeList nlList = eElement.getElementsByTagName(sTag).item(0).getChildNodes(); 
    Node nValue = (Node) nlList.item(0); 
    return nValue.getNodeValue(); 
} 

这个问题似乎是我的阵列是越来越有相同的位置充满3次，结束了用最后的位置填充3次。其他的东西都是很好的形成的，所以我想我得到了正确的部分。

Answer 1

您可以使用XPath，而不是...

public class TestXML03 { 

    public static void main(String[] args) { 

     try { 
      DocumentBuilderFactory factory = DocumentBuilderFactory.newInstance(); 
      factory.setNamespaceAware(false); 
      DocumentBuilder builder = factory.newDocumentBuilder(); 
      Document xmlDoc = builder.parse(new File("Test.xml")); 

      Node root = xmlDoc.getDocumentElement(); 

      XPathFactory xFactory = XPathFactory.newInstance(); 
      XPath xPath = xFactory.newXPath(); 

      XPathExpression xExpress = xPath.compile("/file/location"); 
      NodeList nodes = (NodeList) xExpress.evaluate(root, XPathConstants.NODESET); 

      System.out.println("Found " + nodes.getLength() + " location nodes"); 
      System.out.println(""); 

      for (int index = 0; index < nodes.getLength(); index++) { 
       Node node = nodes.item(index); 
       xExpress = xPath.compile("filmid"); 
       Node filmIDNode = (Node) xExpress.evaluate(node, XPathConstants.NODE); 
       System.out.println(filmIDNode.getNodeName() + " = " + filmIDNode.getTextContent()); 

       xExpress = xPath.compile("date"); 
       Node dateNode = (Node) xExpress.evaluate(node, XPathConstants.NODE); 
       System.out.println(dateNode.getNodeName() + " = " + dateNode.getTextContent()); 

       xExpress = xPath.compile("amount"); 
       Node amountNode = (Node) xExpress.evaluate(node, XPathConstants.NODE); 
       System.out.println(amountNode.getNodeName() + " = " + amountNode.getTextContent()); 

       System.out.println(""); 
      } 

     } catch (Exception exp) { 
      exp.printStackTrace(); 
     } 
    } 
} 

，输出...

Found 3 location nodes 

filmid = 100 
date = 2013-01-11 
amount = 4.00$ 

filmid = 200 
date = 2013-01-13 
amount = 9.00$ 

filmid = 334 
date = 2013-01-23 
amount = 5.00$ 

更新反馈

的Location类保持static引用之后到它的类字段，这意味着改变字段的值会改变它的所有t的实例帽类。

删除static引用，它应该解决问题。

Answer 2

您的源代码正在运行完美。只需将您的源代码修改为如下输出标签。

public static void findLocations(Document document) throws ParseException { 
    NodeList nList = document.getElementsByTagName("location"); 
    Location[] locations = new Location[nList.getLength()]; 
    for (int temp = 0; temp < nList.getLength(); temp++) { 
     Node nNode = nList.item(temp); 

     if (nNode.getNodeType() == Node.ELEMENT_NODE) { 
      Element eElement = (Element) nNode; 
      System.out.println(getTagValue("filmid", eElement)); 
      System.out.println(getTagValue("date", eElement)); 
      System.out.println(getTagValue("amount", eElement)); 
      System.out.println(); 
     } 
    } 
} 

我得到了正确的输出

100 
2013-01-11 
4.00$ 

200 
2013-01-13 
9.00$ 

334 
2013-01-23 
5.00$ 

检查，如果你的XML输入正确。