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我有以下查询,它允许我按行号连接两个表,我试图修改它,以便使用随机名称表中的随机名更新订户表。需要在用户表中随机化名称
select fo.*, so.*
from (select *,
row_number() over (order by FirstName) as rn
from randomnames
) fo
join (select *,
row_number() over (order by ID) as rn
from subscribers) so on fo.rn = so.rn
我把它更新到下面,使其工作
update subscribers set
FirstName = fo.Firstname,
LastName = fo.LastName
from
(select *,
row_number() over (order by firstname) as rn
from _randomnames
) fo
join (select *,
row_number() over (order by ID desc) as rn
from subscribers) so on fo.rn = so.rn
where so.ID = subscribers.ID
我最后想出来的,但因为你回答我接受它。没有真正尝试过,看看它是否工作虽然 – Jhorra
@Jhorra - 我很感激你标记为接受,但你不应该这样做,除非它真的有效,所以它不会混淆未来的读者 – Lamak
@Jhorra:If你找到了你自己的解决方案,你应该发布你的解决方案作为问题的答案。甚至可能接受它。 – Flimzy