我有以下的嵌套JSON对象从这个函数来:转换JSON对象,以一个简单的数组
var jsonData = jQuery.ajax({
url: "http://testsite/_vti_bin/listdata.svc/ProjectHours",
dataType: "json",
async: false
}).responseText;
{
"d": {
"results": [
{
"__metadata": {
"uri": "http://testsite/_vti_bin/listdata.svc/ProjectHours(1)",
"etag": "W/\"1\"",
"type": "Microsoft.SharePoint.DataService.ProjectHoursItem"
},
"ContentTypeID": "0x0100C5D130A92A732D4C9E8489B50657505B",
"Title": "Ryan Cruz",
"Hours": 35,
"Id": 1,
"ContentType": "Item",
"Modified": "/Date(1373535682000)/",
"Created": "/Date(1373535682000)/",
"CreatedBy": {
"__deferred": {
"uri": "http://testsite/_vti_bin/listdata.svc/ProjectHours(1)/CreatedBy"
}
},
"CreatedById": 19,
"ModifiedBy": {
"__deferred": {
"uri": "http://testsite/_vti_bin/listdata.svc/ProjectHours(1)/ModifiedBy"
}
},
"ModifiedById": 19,
"Owshiddenversion": 1,
"Version": "1.0",
"Attachments": {
"__deferred": {
"uri": "http://testsite/_vti_bin/listdata.svc/ProjectHours(1)/Attachments"
}
},
"Path": "/sites/itg/Resourcecenters/spwidgets/Lists/ProjectHours"
},
{
"__metadata": {
"uri": "http://testsite/_vti_bin/listdata.svc/ProjectHours(2)",
"etag": "W/\"1\"",
"type": "Microsoft.SharePoint.DataService.ProjectHoursItem"
},
"ContentTypeID": "0x0100C5D130A92A732D4C9E8489B50657505B",
"Title": "Phillip Phillips",
"Hours": 25,
"Id": 2,
"ContentType": "Item",
"Modified": "/Date(1373535694000)/",
"Created": "/Date(1373535694000)/",
"CreatedBy": {
"__deferred": {
"uri": "http://testsite/_vti_bin/listdata.svc/ProjectHours(2)/CreatedBy"
}
},
"CreatedById": 19,
"ModifiedBy": {
"__deferred": {
"uri": "http://testsite/_vti_bin/listdata.svc/ProjectHours(2)/ModifiedBy"
}
},
"ModifiedById": 19,
"Owshiddenversion": 1,
"Version": "1.0",
"Attachments": {
"__deferred": {
"uri": "http://testsite/_vti_bin/listdata.svc/ProjectHours(2)/Attachments"
}
},
"Path": "/sites/itg/Resourcecenters/spwidgets/Lists/ProjectHours"
}
]
}
}
我想通过每个对象的标题环和时间属性,并将它们保存在的阵列,所以我可以将其传递给谷歌图表如下所示:
var data = google.visualization.arrayToDataTable(array);
我尝试下面的代码,但它不能找到JSON对象:
function drawTable() {
var jsonData = jQuery.ajax({
url: "http://testsite/_vti_bin/listdata.svc/ProjectHours",
dataType: "json",
async: false
}).responseText;
alert(jsonData);
var obj = jQuery.parseJSON(jsonData);
//alert(jsonData.length);
var sampleData = [], results = d.results;
for (var i = 0, len = results.length; i < len; i++) {
var result = results[i];
sampleData.push({ Title: result.Title, Hours: result.Hours});
}
var data = google.visualization.arrayToDataTable(obj);
var chart = new google.visualization.PieChart(document.getElementById('spChart'));
chart.draw(data, {showRowNumber: true});
}
请给我一些想法,以便我在这一天的其余时间不会卡在这里。谢谢!
JSON回调的范围内是否存在循环结构? – DevlshOne
你怎么定义'd'? –
@DevlshOne没有JSON回调。他使用'async:false'和'responseText'(这是可怕的imo,但不是问题) –