链接输入文件我尝试编译存储在一个子目录下生成对象的一个项目:Makefile文件 - 从文件夹
myproject:
|
src: .cpp, .cpp ...
|
release: .o, .o ...
这里的Makefile的一部分:
SRC ?= src
OBJ_PATH = $(SRC)/Release
vpath %.o $(OBJ_PATH)
...
OBJS := $(addprefix $(OBJ_PATH)/,obj1.o obj2.o)
all: build
obj1.o: $(SRC)/Manager.cpp
$(EXEC) $(CC) $(INCLUDES) $(CCFLAGS) $(GNCD_FLGS) -c $(<) -o $(OBJ_PATH)/[email protected] #-o [email protected] -c $<
obj2.o: $(SRC)/Synth.cpp
$(EXEC) $(CC) $(INCLUDES) $(CCFLAGS) $(GNCD_FLGS) $(DEFS) -c $(<) -o $(OBJ_PATH)/[email protected] #-o [email protected] -c $<
myApp: obj1.o obj2.o
$(EXEC) $(CC) $(LDFLAGS) $(GNCD_FLGS) -o [email protected] $(OBJS) $+ $(LIBS)
$(EXEC) mkdir -p $(OBJ_PATH)/$(TRGT_ARCH)/$(TRGT_OS)/$(BLD_TP)
$(EXEC) cp [email protected] $(OBJ_PATH)/$(TRGT_ARCH)/$(TRGT_OS)/$(BLD_TP)
$(OBJECTS) : Stt.h
build: myApp
run: build
$(EXEC) ./myApp
..但我有一个错误的链接:
Could not open input file 'obj1.o'
Makefile:86: recipe for target 'myApp' failed
所以看起来在src/Release dir中找不到对象;
有什么想法?
感谢的
这是http://stackoverflow.com/questions/13552575/gnu-make-pattern-to-build-output-in-different-directory-than-src的副本? –
是的,这听起来很有趣,但在我的情况下,我需要从项目源和外部库创建对象。所以,我不知道得到这个语法能够既对象链接.. – spin0