我怎样才能得到zipfile实例与UI包装

Question

我一直在尝试使用类库appJar这是一个很好的Python基本用户界面。我有工作的代码执行，我需要，但是，当我环绕它的用户界面，它不运行的功能，UI的对破发点

远不及反馈相关的代码是在这里：

def zipdir(path, ziph): 
# ziph is zipfile handle 
for root, dirs, files in os.walk(fromDirectory): 
    for file in files: 
     with Archive.progressbar.progressbar(max_value=10) as progress: 
      for i in range(1): 
       filePath = os.path.join(root, file) 
       ziph.write(filePath, relpath(filePath, "")) 
       time.sleep(0.1) 
       progress.update(i) 
def beginBackup(btn): 
    return app.questionBox("Ready?", "Click OK ") 

上面设置了功能，及以下应该运行它，但它不

try: 
    if (beginBackup == True): 
     print(beginBackup) 
     zipf = zipfile.ZipFile('Python.zip', 'w', zipfile.ZIP_DEFLATED) 
     zipdir('tmp/', zipf) 
     zipf.close() 
     os.rename('Python.zip', "bak" + str(fileName) + ".zip") 
     shutil.move("bak" + str(fileName) + ".zip", str(toDirectory) + "/bak" + str(fileName) + ".zip") 
else: 
    raise Exception("Something went wrong") 
except Exception as e: 
    app.warningBox("Error", "Something went wrong: {}".format(str(e))) 

我觉得这是因为我把代码中错误的地方，因为这感觉就像它从来没有实例化备份过程。

下面是完整的代码：

import os 
import zipfile 
import shutil 
import time 
from os.path import relpath 
from appJar import gui 

# Global Variables 
fromDirectory = "" 
toDirectory = "" 
fileName = time.time() 
fileVersion = 1.2 

# Setting up the mechanism 
def backupsource(btn): 
    fromDirectory = app.directoryBox(title="Source") 

def backupdest(btn): 
    toDirectory = app.directoryBox(title="Destination") 

def zipdir(path, ziph): 
    # ziph is zipfile handle 
    for root, dirs, files in os.walk(fromDirectory): 
     for file in files: 
      with Archive.progressbar.progressbar(max_value=10) as progress: 
       for i in range(1): 
        filePath = os.path.join(root, file) 
        ziph.write(filePath, relpath(filePath, "")) 
        time.sleep(0.1) 
        progress.update(i) 
def beginBackup(btn): 
    return app.questionBox("Ready?", "Click OK ") 

# Open the GUI 
app = gui() 
app.showSplash("Simple zip v. 1.2", fill="grey", stripe="#ADDFAD", fg="white", font=44) 

# Setup the visual styles of the app 
app.setTitle("Simple Zip") 
app.setIcon("img/logo.ico") 
app.setGeometry(400, 300) 
app.setResizable(canResize=True) 

# Items inside of the GUI 
app.addLabel("title", "Welcome to the simple backup utility") 
app.setLabelBg("title", "gray") 
app.addLabel("Backup", "Label goes here") 

# Setup source buttons 
app.addButton("Source", backupsource) 
app.addButton("Destination", backupdest) 

# Begin Backup section 
app.addButton("Backup!", beginBackup) 

# start the GUI 
app.go() 

try: 
    if (beginBackup == True): 
     print(beginBackup) 
     zipf = zipfile.ZipFile('Python.zip', 'w', zipfile.ZIP_DEFLATED) 
     zipdir('tmp/', zipf) 
     zipf.close() 
     os.rename('Python.zip', "bak" + str(fileName) + ".zip") 
     shutil.move("bak" + str(fileName) + ".zip", str(toDirectory) + "/bak" + str(fileName) + ".zip") 
else: 
    raise Exception("Something went wrong") 

except Exception as e: 
     app.warningBox("Error", "Something went wrong: {}".format(str(e))) 

Answer 1

我察觉第一个错误是os.renames，它不存在。但我不能建议像这样发现错误。我已经重写与例外包装（和短路无用rename命令，因为shutil.move可以处理重命名+跨文件系统移动。

然后你做app.go()但没有经过这一行。这是GUI主循环。从目前来看，appJar分派事件你有没有关于主程序控制了

所以一切都必须在这里完成（当你按下按钮的代码激活）：

def beginBackup(btn): 
    return app.questionBox("Ready?", "Click OK ") 

弹出一个窗口，并不会仅此而已。它应该被替换由全码：

def beginBackup(btn): 
    if not app.questionBox("Ready?", "Click OK"): 
     app.warningBox("Error", "Cancelled") 
    else: 
     try: 
     zipf = zipfile.ZipFile('Python.zip', 'w', zipfile.ZIP_DEFLATED) 
     zipdir('tmp/', zipf) 
     zipf.close() 
     shutil.move('Python.zip', str(toDirectory) + "/bak" + str(fileName) + ".zip") 
     except Exception as e: 
     app.warningBox("Error", "Something went wrong: {}".format(str(e))) 

所以现在如果有什么在回调发生，你会得到一个很好的警告框，告诉你它到底是什么（无法​​打开文件，语法错误等）