2014-01-26 37 views

回答

1

你基本上需要创建一个带有参数的新进程,这个参数是你的文本框的输入。然后,你可以捕捉程序的输出,将其存储在一个变量,并显示在对话框中。

这里有一个小片断:

Dim command As String = "C:\My Dir\MyFile.exe" 
Dim args As String = "MyParam1 MyParam2" 

Dim proc = New Process() With { _ 
    Key .StartInfo = New ProcessStartInfo() With { _ 
    Key .FileName = "program.exe", _ 
    Key .Arguments = args, _ 
    Key .UseShellExecute = False, _ 
    Key .RedirectStandardOutput = True, _ 
    Key .CreateNoWindow = True _ 
    } _ 
} 

proc.Start() 

While Not proc.StandardOutput.EndOfStream 
    Dim line As String = proc.StandardOutput.ReadLine() 
    ' do something with the line 
End While 
+0

谢谢!还有一种方法可以将输入提供给控制台吗? –

+0

不客气:)嗯,你可以使用命令行参数来启动你的程序(如上所述)。然后,你可以发送键击产生的进程。检查这个问题的方式来做到这一点:http://stackoverflow.com/questions/2686865/how-can-i-send-keypresses-to-a-running-process-object –

0

下面是一些样板代码(确保有txtInputtxtOutput的形式):

Private m_process As Process 
Private m_encoding_for_program As System.Text.Encoding 

Private Sub Form1_Load(ByVal sender As Object, ByVal e As System.EventArgs) Handles Me.Load 

    m_encoding_for_program = System.Text.Encoding.GetEncoding(866) 'Adjust as needed 

    Dim psi As New ProcessStartInfo 
    psi.CreateNoWindow = True 
    psi.UseShellExecute = False 
    psi.FileName = "cmd.exe" 
    psi.RedirectStandardInput = True 
    psi.RedirectStandardError = True 
    psi.StandardErrorEncoding = m_encoding_for_program 
    psi.RedirectStandardOutput = True 
    psi.StandardOutputEncoding = m_encoding_for_program 

    m_process = Process.Start(psi) 
    AddHandler m_process.OutputDataReceived, AddressOf OutputDataReceived 
    AddHandler m_process.ErrorDataReceived, AddressOf OutputDataReceived 'Make different handler if needed. 
    m_process.BeginOutputReadLine() 
    m_process.BeginErrorReadLine() 

End Sub 

Private Sub Form1_FormClosed(ByVal sender As Object, ByVal e As System.Windows.Forms.FormClosedEventArgs) Handles Me.FormClosed 
    m_process.CancelOutputRead() 
    m_process.CancelErrorRead() 
    m_process.Kill() 
End Sub 

Private Sub TextBox1_KeyUp(ByVal sender As Object, ByVal e As System.Windows.Forms.KeyEventArgs) Handles txtInput.KeyUp 
    If e.KeyCode = Keys.Enter Then 
     Dim b = m_encoding_for_program.GetBytes(txtInput.Text) 
     m_process.StandardInput.BaseStream.Write(b, 0, b.Length) 
     m_process.StandardInput.WriteLine() 
    End If 
End Sub 

Private Sub OutputDataReceived(ByVal sender As Object, ByVal e As DataReceivedEventArgs) 
    Me.Invoke(CType(AddressOf Me.ThreadProcSetter, Action(Of Object)), e.Data) 
End Sub 

Private Sub ThreadProcSetter(ByVal text As Object) 
    txtOutput.AppendText(DirectCast(text, String) & ControlChars.NewLine) 
End Sub 

txtInput输入命令,然后按回车看结果。确保txtOutput是多行。
添加错误需要检查。

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