1
我有一个从服务器拉出的作业对象数组,以及从服务器拉出的一组人对象。我希望个人作业由一个select元素表示,从jobs数组填充。我已经使用ng-options填充了select,并且在更改选择时,更新了人员模型的作业对象。我唯一的问题是,从select开始显示一个空值。我不知道如何让它显示人物对象当前的工作?Angularjs选择 - 基于模型设置初始选择
<select
ng-model='person.job'
ng-options='job.title for job in jobs'>
</select>
人物对象看起来像这样
{
"id": "1",
"firstName": "Marianne",
"lastName": "Jenkins",
"middleNames": null,
"ext": "4680",
"phoneCell": "1-174-668-3846",
"phoneHome": "+10(2)5744088105",
"takerNumber": "180",
"hidden": "0",
"created_at": "2014-01-09 12:55:12",
"updated_at": "2014-01-09 12:55:12",
"job": {
"id": "25",
"title": "Office Manager",
"created_at": "2014-01-09 12:55:11",
"updated_at": "2014-01-09 19:25:03"
},
"office": {
"id": "4",
"name": "Salt Lake City",
"prefix": "702",
"order": "2",
"takerNumber": "103",
"address_id": "1"
}
}
和就业阵列看起来像我提供足够的信息和遗憾,这
[
{
"id": "1",
"title": "Field Service Tech",
"created_at": "2014-01-09 12:55:11",
"updated_at": "2014-01-09 19:25:03"
},
{
"id": "2",
"title": "Inside Sales Manager",
"created_at": "2014-01-09 12:55:11",
"updated_at": "2014-01-09 19:25:03"
},
{
"id": "3",
"title": "Office Assistant",
"created_at": "2014-01-09 12:55:11",
"updated_at": "2014-01-09 19:25:03"
},
...
{
"id": "25",
"title": "Office Manager",
"created_at": "2014-01-09 12:55:11",
"updated_at": "2014-01-09 19:25:03"
}
...
]
希望如果我的描述是有点不清楚,我努力了一下,准确地描述了我的问题。
在此先感谢!
注意:此处显示的人是生成的并且不是真实的。
谢谢你做的伎俩! –