我想要做一个选择查询使用JavaScript参数($ userCard)获取在同一个函数(代码下面)。但给出了一个未定义的变量错误,如何在查询中传递参数?选择查询使用JavaScript的文字
<script>
function count() {
$card = "V010";
$userCard = document.getElementById('visitorID');
if($userCard.value.length == 4){
<?php
$connection = connectToSql();
$query = "SELECT * FROM visitorsystem.visitor WHERE cardNo = '$userCard' ";
$result = mysqli_query($connection,$query)
or die("Error in query: ". mysqli_error($connection));
if(mysqli_fetch_assoc($result) >0)
{
echo "Card in Use";
}
?>
}
}
</script>
你希望获得价值? '$ userCard = document.getElementById('visitorID').value' - 很难猜测没有看到你的html –