自定义XML序列化我有我想要序列下面的类结构:与继承
[XmlRoot("SomeClass")]
public class SomeClass
{
private BaseClass[] _itemArray;
public BaseClass[] ItemArray
{
get { return _itemArray; }
set { _itemArray = value; }
}
public PPSPStatReportMessage()
: base()
{
}
}
public class SomeOtherClass
{
private int _property5;
[XmlAttribute("Property5")]
public int Property5
{
get { return _property5; }
set { _property5 = value; }
}
private string _property6;
[XmlText()]
public string Property6
{
get { return _property6; }
set { _property6 = value; }
}
public SomeOtherClass()
{
}
}
[XmlInclude(typeof(DerivedClass1))]
[XmlInclude(typeof(DerivedClass2))]
[XmlRoot("BaseClass")]
[XmlType("")]
public class BaseClass
{
private string _property1;
[XmlAttribute("Property1")]
public string Property1
{
get { return _property1; }
set { _property1 = value; }
}
public SomeClass(string PropertyVal)
{
_property1 = PropertyVal;
}
}
[XmlRoot("BaseClass")]
[XmlTypeAttribute(Namespace = "")]
public class DerivedClass1 : BaseClass
{
private string _property2;
[XmlAttribute("Property2")]
public string Property2
{
get { return _property2; }
set { _property2 = value; }
}
private SomeOtherClass _property3;
[XmlElement("SomeOtherClass")]
public SomeOtherClass Property3
{
get { return _property3; }
set { _property3 = value; }
}
public DerivedClass()
: base("PropertyVal1")
{
}
}
[XmlRoot("BaseClass", Namespace = "")]
[XmlType("")]
public class DerivedClass2 : BaseClass
{
private Int64 _property4;
[XmlAttribute("Property4")]
public Int64 Property4
{
get { return _property4; }
set { _property4 = value; }
}
public DerivedClass2()
: base("PropertyVal2")
{
}
}
这是我使用的序列化SomeClass的方法:
public static string SerializeXML(object Value, System.Type ObjectType)
{
XmlSerializer serializer = new XmlSerializer(ObjectType);
XmlSerializerNamespaces namespaceSerializer = new XmlSerializerNamespaces();
namespaceSerializer.Add("", "");
StringWriter ms = new StringWriter();
serializer.Serialize(ms, Value, namespaceSerializer);
return ms.ToString();
}
这种方法生成的XML结构看起来像下面这样:
<?xml version="1.0" encoding="utf-16"?>
<SomeClass>
<ItemArray>
<BaseClass d3p1:type="DerivedClass1" Property1="PropertyVal1" Property2="123" xmlns:d3p1="http://www.w3.org/2001/XMLSchema-instance">
<SomeOtherClass Property5="0" >STRING DATA</SomeOtherClass>
</BaseClass>
<BaseClass d3p1:type="DerivedClass2" Property="PropertyVal2" Property4="456" xmlns:d3p1="http://www.w3.org/2001/XMLSchema-instance" />
</ItemArray>
</SomeClass>
但是,我需要省略d3p1:type和xm LNS:d3p1属性,并生成一个XML结构是这样的:
<?xml version="1.0" encoding="utf-16"?>
<SomeClass>
<ItemArray>
<BaseClass Property1="PropertyVal1" Property2="123">
<SomeOtherClass Property5="0" >STRING DATA</SomeOtherClass>
</BaseClass>
<BaseClass Property="PropertyVal2" Property4="456" />
</ItemArray>
</SomeClass>
正如你可以在代码中看到,我试图用XmlType将和XmlTypeAttribute,但没有成功。
有关如何生成上述XML结构(不包括d3p1:type和xmlns:d3p1属性)的任何建议?
XmlSerializer.Deserialize需要它才能正常工作。你从来没有反序列化? – 2011-03-02 16:57:25
我在序列化,但我检查“Property”属性以知道将使用哪个对象类型进行反序列化。 – IraqiGeek 2011-03-02 18:27:28
Meant反序列化... – IraqiGeek 2011-03-02 18:27:59