批量启动路径\此文件的文件名称

Question

标题有点含糊，我不知道如何说出它。

我该怎么做。 运行文件的开始路径\文件名。

有点像启动路径\％0这是有点什么，我正在尝试做，但如果我这样做，它会拿出像波纹管的东西。

复制C：\ Users \用户名\桌面\文件夹\ C：\ Users \用户名\桌面\ batch.bat

我只想C：\ Users \用户名\桌面\文件夹\ batch.bat batch.bat是文件名，如果你重命名批处理文件，这个必须改变。

对不起，如果我解释得很糟糕。

Answer 1

你可以用一些for诡计做到这一点：

@setlocal enableextensions enabledelayedexpansion 
@echo off 
echo %0 
for %%f in (%0) do set basename=%%~nf 
echo Will run \arbitrary-path\%basename% 
endlocal 

的%%~nf给你%%f变量的名称，没有路径或扩展。如果你喜欢的东西运行：

C:\Users\Pax\qq.cmd 

，你会看到类似这样的：

c:\Users\Pax\qq.cmd 
Will run \arbitrary-path\qq 

你可以看到所有的其他有用的扩展，如果你键入for /?到命令行窗口：

%~I   - expands %I removing any surrounding 
        quotes (") 
    %~fI  - expands %I to a fully qualified path 
        name 
    %~dI  - expands %I to a drive letter only 
    %~pI  - expands %I to a path only 
    %~nI  - expands %I to a file name only 
    %~xI  - expands %I to a file extension only 
    %~sI  - expanded path contains short names 
        only 
    %~aI  - expands %I to file attributes of file 
    %~tI  - expands %I to date/time of file 
    %~zI  - expands %I to size of file 
    %~$PATH:I - searches the directories listed in 
        the PATH environment variable and 
        expands %I to the fully qualified 
        name of the first one found. If the 
        environment variable name is not 
        defined or the file is not found by 
        the search, then this modifier 
        expands to the empty string 

修饰符可以结合得到复合结果：

%~dpI  - expands %I to a drive letter and 
        path only 
    %~nxI  - expands %I to a file name and 
        extension only 
    %~fsI  - expands %I to a full path name with 
        short names only 
    %~dp$PATH:I - searches the directories listed in 
        the PATH environment variable for 
        %I and expands to the drive letter 
        and path of the first one found. 
    %~ftzaI  - expands %I to a DIR like output line