通过DOM解析多个URL。 PHP @ $ dom-> loadHTML（$ html。$ html2）;

Question

我想解析2个使用PHP DOM的网址。我想知道是否有人能够向我提供有关我出错地点的信息？是否无法像我在下面所做的那样解析这两个URL？

<?php 
$html = file_get_contents('http://www.reddit.com/r/funny'); 
$html2 = file_get_contents('http://www.9gag.com/'); 
$dom = new DOMDocument(); 
@$dom->loadHTML($html.$html2); 

$xpath = new DOMXPath($dom); 
$hyperlinks = $xpath->evaluate('//a[@class="thumbnail "]'); 
$hyperlinks2 = $xpath->evaluate('//a[@class="badge-item-img"]'); 

foreach($hyperlinks as $hyperlink) { 
if(strpos($hyperlink->getAttribute('href'), 'http://i.imgur.com/') !== FALSE){ 
echo "<img style='padding-left:30%' width=\"500\" src=\"" . $hyperlink->getAttribute('href') . "\" alt=\"\" />"; 
    echo "<br>"; 
    echo "<br>"; 
    echo "<br>"; 

} 
    else{ 
     echo ""; 
    } 
} 
?> 

编辑此编辑已作为我试图做比较的类=“徽章项-IMG”，它不是返回任何东西。难道我没有这样做吗？

<?php 
// Init the '$url_array' array. 
$url_array = array(); 
$url_array[] = 'http://www.reddit.com/r/funny'; 
$url_array[] = 'http://www.9gag.com/'; 

// Init the return '$ret' array. 
$ret = array(); 

// Roll through the '$url_array' array. 
foreach ($url_array as $url_value) { 
    $html = file_get_contents($url_value); 
    $dom = new DOMDocument(); 
    $dom2 = new DOMDocument(); 
    @$dom->loadHTML($html); 

    $xpath = new DOMXPath($dom); 
    $xpath2 = new DOMXPath($dom2); 
    $hyperlinks = $xpath->evaluate('//a[@class="thumbnail "]'); 
    $hyperlinks2 = $xpath2->evaluate('//a[@class="badge-item-img"]'); 

    foreach($hyperlinks as $hyperlink) { 
    if(strpos($hyperlink->getAttribute('href'), 'http://i.imgur.com/') !== FALSE){ 
     $ret[] = "<img style='padding-left:30%' width=\"500\" src=\"" . $hyperlink->getAttribute('href') . "\" alt=\"\" />" 
      . "<br>" 
      . "<br>" 
      . "<br>" 
      ; 

    } 
    foreach($hyperlinks2 as $hyperlinker) { 
      $ret[] = "<img style='padding-left:30%' width=\"500\" src=\"" . $hyperlinker->getAttribute('href') . "\" alt=\"\" />" 
      . "<br>" 
      . "<br>" 
      . "<br>" 
      ; 
    } 
    } 
    } 
// Roll through the '$ret' array. 
foreach($ret as $ret_value) { 
    echo $ret_value; 
} 

Answer 1

好像你正试图将一个HTML文件的内容合并到另一个HTML文件的顶部。这最终会导致一个很可能会阻塞DOM解析器的文档。相反，您应该循环访问网址&，然后输出结果：

<?php 

// Init the '$url_array' array. 
$url_array = array(); 
$url_array[] = 'http://www.reddit.com/r/funny'; 
$url_array[] = 'http://www.9gag.com/'; 

// Init the return '$ret' array. 
$ret = array(); 

// Roll through the '$url_array' array. 
foreach ($url_array as $url_value) { 
    $html = file_get_contents($url_value); 
    $dom = new DOMDocument(); 
    @$dom->loadHTML($html); 

    $xpath = new DOMXPath($dom); 
    $hyperlinks = $xpath->evaluate('//a[@class="thumbnail "]'); 
    $hyperlinks2 = $xpath->evaluate('//a[@class="badge-item-img"]'); 

    foreach($hyperlinks as $hyperlink) { 
    if(strpos($hyperlink->getAttribute('href'), 'http://i.imgur.com/') !== FALSE){ 
     $ret[] = "<img style='padding-left:30%' width=\"500\" src=\"" . $hyperlink->getAttribute('href') . "\" alt=\"\" />" 
      . "<br>" 
      . "<br>" 
      . "<br>" 
      ; 
    } 
    } 
} 

// Roll through the '$ret' array. 
foreach($ret as $ret_value) { 
    echo $ret_value; 
} 

?> 

Answer 2

我不确定是否看到问题。我在本地测试了这个代码，它工作。你是否收到某种错误？