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我有一个访问REST服务的骆驼路由。事情工作正常,如果REST响应是200好的。但是,如果响应是404,则REST服务会返回有效负载中的一些其他信息,而我无法找到访问方式。如何从Camel cxfrs中的REST 404响应中访问有效内容?
这是从运行它的调试日志的一部分:
[Camel (rraaCamelContext) thread #2 - seda://from_rraa] INFO org.apache.cxf.interceptor.LoggingInInterceptor - Inbound Message
----------------------------
ID: 2
Response-Code: 404
Encoding: ISO-8859-1
Content-Type: application/json
Headers: {Accept=[application/json], breadcrumbId=[ID-Steves-MacBook-Pro-local-53701-1446241733043-1-7], content-type=[application/json], OriginalHeader=[{name=VerifyEmployeeRequest, version=1, scac=rraa, timeSent=null, uuid=abcd-1234}], pin=[1234], reason=[INIT], Server=[Jetty(9.2.11.v20150529)], transfer-encoding=[chunked], User-Agent=[Apache CXF 3.1.2]}
Payload: { "employeeID": "bad-name", "message": "id not found" }
我的路线设置为:
<route id="rraaIss">
<from uri="seda:from_rraa"/>
<process ref="issPreprocessor"/>
<unmarshal ref="IssRequest"/>
<process ref="webServiceProcessor"/>
<to uri="cxfrs:bean:webService"/>
<onException>
<exception>javax.ws.rs.NotFoundException</exception>
<handled><constant>true</constant></handled>
<to uri="bean:crewServiceNotFoundProcessor"/>
</onException>
<process ref="packageWebServiceReplyForIss"/>
<to uri="seda:to_rraa"/>
</route>
我crewServiceNotFoundProcessor
豆被调用时,响应404它可以看到异常,但是我怎样才能从原始的HTTP响应中获得有效载荷?